2013-11-25 83 views
1

如何通過提交HTML文件上傳表單將文件上傳到服務器?提交HTML文件上傳表格

的HTML代碼如下所示:

<form action="upload.php" method="post" enctype="multipart/form-data"> 
<label for="file">Filename:</label> 
<input type="file" name="file" id="file"><br> 
<input type="submit" name="submit" value="Submit"> 
</form> 
+0

我建議你最好使用後面的代碼來做到這一點.. – User2012384

+0

@ user2725580,這是一個C#或PHP的問題? –

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c#作爲標籤指定。 – user2725580

回答

0

這是一個通過HTML表單接受文件的一個簡單的例子:

<html> 
<body> 

<form action="upload_file.php" method="post" 
enctype="multipart/form-data"> 
<label for="file">Filename:</label> 
<input type="file" name="file" id="file"><br> 
<input type="submit" name="submit" value="Submit"> 
</form> 

</body> 
</html> 

在您的文件upload_file.php,提出:

<?php 
$allowedExts = array("gif", "jpeg", "jpg", "png"); 
$temp = explode(".", $_FILES["file"]["name"]); 
$extension = end($temp); 
    if ($_FILES["file"]["error"] > 0) 
    { 
    echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; 
    } 
    else 
    { 
    echo "Upload: " . $_FILES["file"]["name"] . "<br>"; 
    echo "Type: " . $_FILES["file"]["type"] . "<br>"; 
    echo "Size: " . ($_FILES["file"]["size"]/1024) . " kB<br>"; 
    echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>"; 

    if (file_exists("upload/" . $_FILES["file"]["name"])) 
     { 
     echo $_FILES["file"]["name"] . " already exists. "; 
     } 
    else 
     { 
     move_uploaded_file($_FILES["file"]["tmp_name"], 
     "upload/" . $_FILES["file"]["name"]); 
     echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; 
     } 
    } 
    } 
else 
    { 
    echo "Invalid file"; 
?> 

來源:http://www.w3schools.com/php/php_file_upload.asp