-4
我很難刪除數組中的元素。我已經嘗試了一會兒，並且正在試圖弄清楚這一點，我正在毆打我的頭。我將不勝感激任何幫助。如何刪除數組中的元素？
package javaapplication9;
import java.util.Scanner;
import java.util.ArrayList;
public class JavaApplication9 {
int x;
final int maxContacts = 3;
final String[] FIRSTNAME = { "Josh", "Joe", "Jim" };
final String[] LASTNAME = { "Jones", "Smith", "Thomas" };
final String[] ADDRESS =
{ "142 Washington Ave", "500 Main St", "200 Oak Way" };
final String[] CITY = { "Pittsburgh", "Pittsburgh", "Pittsburgh" };
final String[] STATE = { "PA", "PA", "PA" };
final String[] ZIP = { "15222", "15222", "15222" };
final String[] TELEPHONE =
{ "412-722-1500", "412-498-2500", "412-787-3500" };
String[]firstName = new String[3];
String[]lastName = new String[3];
String[]address = new String[3];
String[]city = new String[3];
String[]state = new String[3];
String[]zip = new String[3];
String[]telephone = new String[3];
String nameSearch;
boolean firstNameFound = true, lastNameFound = true, addressFound =
true, cityFound = true, stateFound = true, zipFound =
true, telephoneFound = true;
Scanner keyboard = new Scanner(System.in);
public void getInfo() {
while (x < maxContacts) {
Scanner input = new Scanner(System.in);
System.out.
println
("Enter '1' To Add A Contact \nEnter '2' To Delete A Contact \nEnter '3' To Search For A Name \nEnter '4' To Display All Contacts \nEnter 'Q' To Quit");
int usersChoice = input.nextInt();
if (usersChoice == 1) {
System.out.print("Please enter a first name: ");
firstName[x] = keyboard.nextLine();
if (firstNameFound) {
System.out.
print("Please enter a last name: ");
lastName[x] = keyboard.nextLine();
}
if (lastNameFound) {
System.out.
print("Please enter an address: ");
address[x] = keyboard.nextLine();
}
if (addressFound) {
System.out.
print("Please enter a city: ");
city[x] = keyboard.nextLine();
}
if (cityFound) {
System.out.
print("Please enter a state: ");
state[x] = keyboard.nextLine();
}
if (stateFound) {
System.out.
print("Please enter a zip: ");
zip[x] = keyboard.nextLine();
}
if (zipFound) {
System.out.
print
("Please enter a telephone number: ");
telephone[x] = keyboard.nextLine();
}
}
if (usersChoice == 4) {
System.out.println("\nList Of Contacts");
System.out.
println("------------------------------");
for (int i = 0; i < FIRSTNAME.length; i++) {
System.out.println("First Name: " +
FIRSTNAME[i] +
"\nLast Name: " +
LASTNAME[i] +
"\nAddress: " +
ADDRESS[i]
+ "\nCity: " +
CITY[i] +
"\nState: " +
STATE[i] +
"\nZip: " + ZIP[i] +
"\nTelephone: " +
TELEPHONE[i] +
"\n-------------------------\n");
}
for (int i = 0; i < firstName.length; i++) {
System.out.println("First Name: " +
firstName[i] +
"\nLast Name: " +
lastName[i] +
"\nAddress: " +
address[i]
+ "\nCity: " +
city[i] +
"\nState: " +
state[i] +
"\nZip: " + zip[i] +
"\nTelephone: " +
telephone[i]);
}
}
if (usersChoice == 3) {
System.out.print("\n\nPlease enter a name to find ");
// no idea how to
// search a name and
// display the
// corresponding
// number!
nameSearch = keyboard.next();
for (int i = 0; i < firstName.length; i++) {
if (nameSearch.equals(firstName[i])) {
System.out.println("The name " +
firstName[i]
+
" was found "
+
"with the phone number "
+
firstName
[i]);
}
}
}
}
}
public static void main(String args[]) {
JavaApplication9 show = new JavaApplication9();
show.getInfo();
}
}
這陣你想從刪除？你是如何嘗試從中刪除的？你能在十行程序中重現你的問題而不是這段代碼？ – sarnold
在此代碼中沒有真正的嘗試刪除操作，它將成爲userChoice爲2時的最後一個if else語句（讀取getInfo開始處的菜單選項） – Snicolas