5
我在SQLite中有一個表我想在該表中插入數據。該表具有respond_id,participant_id,answer_text,answer_option_update_date_time。 respond_id和participant_id是整數。當我將任何事情分配給participant_id時,它會發出錯誤,對象無法設置爲屬性。在iPhone App中分配NSInteger屬性
@interface Coffee : NSObject {
NSInteger coffeeID;
NSInteger participant_Id;
NSString*question_Id;
NSString*answer_option;
NSString*answer_text;
NSString*update_date_time;
//Intrnal variables to keep track of the state of the object.
}
@property (nonatomic, readonly) NSInteger coffeeID;
@property (nonatomic, retain) NSInteger participant_Id;
@property (nonatomic, copy) NSString *question_Id;
@property (nonatomic, copy) NSString *answer_option;
@property (nonatomic, copy) NSString *answer_text;
@property (nonatomic, copy) NSString *update_date_time;
- (void)save_Local {
CereniaAppDelegate *appDelegate = (CereniaAppDelegate *)[[UIApplication sharedApplication] delegate];
Coffee *coffeeObj = [[Coffee alloc] initWithPrimaryKey:0];
coffeeObj.participant_Id=mynumber;
NSString*question="1";
coffeeObj.question_Id=question;
coffeeObj.answer_option=selectionAnswerOption;
coffeeObj.answer_text=professionTextField.text;
NSDate* date = [NSDate date];
NSDateFormatter* formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"yyyy-MM-dd HH:MM:SS"];
NSString* str = [formatter stringFromDate:date];
UPDATE_DATE_TIME=str;
coffeeObj.update_date_time=UPDATE_DATE_TIME;
//Add the object
[appDelegate addCoffee:coffeeObj];
}
當我將值賦給participant_id時,它會給出錯誤。
感謝它爲我工作 –
如果你確實希望它是一個對象,你可以將它包裝在一個'NSNumber'中。 – QED
沒問題。人們常常認爲「NSInteger」和「NSUInteger」是類。 – mttrb