2012-04-26 148 views
0

我仍然是新的slickgrid,所以我試圖遵循使用DataView與SlickGrid jQuery插件的簡單示例。但是我無法弄清楚數據是如何添加到DataView的。如何在slickgrid中添加複選框?

這裏的代碼:

$data = ''; 
$i = 0; 

$query = "SELECT * FROM tahun"; 
$result = mysql_query($query); 
while($row = mysql_fetch_array($result)){ 
    $data .= ' 
     data['.$i.'] = { 

      spt: "'.$row['ID'].'", 
      nama: "'.$row['nama'].'", 
      alamat: "'.$row['alamat'].'", 
      bayar: "'.$row['tanggal_bayar'].'", 
      hutang: "'.$row['tanggal_hutang'].'", 
      perkiraan: "'.$row['perkiraan'].'", 
     }; 
    '; 
    $i++; 
} 



var grid; 
    var columns = [ 

     {id:"spt", name:"ID", field:"spt",sortable: true}, 
     {id:"nama", name:"Nama", field:"nama",sortable: true}, 
     {id:"alamat", name:"Alamat", field:"alamat",sortable: true}, 
     {id:"bayar", name:"Bayar", field:"bayar",sortable: true}, 
     {id:"hutang", name:"Hutang", field:"hutang",sortable: true}, 
     {id:"perkiraan", name:"Perkiran", field:"perkiraan",sortable: true} 

    ]; 

    var options = { 
     enableCellNavigation: true, 
     enableColumnReorder: false, 
     multiColumnSort: true, 
     editable: true, 
     asyncEditorLoading: false, 
     autoEdit: false 
    }; 
    var columns = []; 

    $(function() { 
     var checkboxSelector = new Slick.CheckboxSelectColumn({ 
     cssClass: "slick-cell-checkboxsel" 
    }); 
    columns.push(checkboxSelector.getColumnDefinition()); 

    columns.push({ 
     var data = []; 
     <?=$data?> //This is where we echo the PHP variable $data which contains our JavaScript array as a string. 
     }); 
     grid = new Slick.Grid($("#myGrid"), data, columns, options); 

    grid.setSelectionModel(new Slick.RowSelectionModel({selectActiveRow: false})); 
    grid.registerPlugin(checkboxSelector); 

我是不知道如何在代碼添加ID爲複選框以上。 這裏的代碼 https://rapidshare.com/files/3188523206/slickgrid.rar

回答

0

你上面的代碼示例和問題標題完全不相關。你能否重新解釋這個問題或提供相關的代碼?你提到DataView - 但你上面的代碼根本不使用DataView。