如何從字典swift3

-3

獲得價值我有Dictionary這樣，我得到「OutputResult」的價值，但我怎麼弄「的company_id」的價值，「部門」等。如何從字典swift3

if let convertedJsonIntoDict = try JSONSerialization.jsonObject(with: data!, options: []) as? NSDictionary 


let firstNameValue = convertedJsonIntoDict["OutputResult"] as? String 
       print("OutputResult is :\(firstNameValue!)") 

{ 
OutputResult = true; 
msg =  { 
    "company_id" = 1; 
    "department_id" = 6; 
    email = "[email protected]"; 
    "employee_code" = 014; 
    "employee_id" = 131; 
    "employee_name" = "abc dsc"; 
    "have_power" = 0; 
    ip = ""; 
    "is_deleted" = 0; 
    lastactivity = ""; 
    status = 1; 
}; 
}

來源

2016-12-07 johnyDiOS

您需要使用快速原生Dictionary而不是NSDictionary，它會讓您從Dictionary輕鬆訪問。從您的迴應看起來像OutputResult包含Boolean值，也是你的company_id和department_id是在另一個字典msg所以你嘗試下面的東西。

if let convertedJsonIntoDict = try JSONSerialization.jsonObject(with: data!, options: []) as? [String: Any] { 
    if let msg = convertedJsonIntoDict["msg"] as? [String: Any], let company_id = msg["company_id"] as? Int, 
     let department_id = msg["department_id"] as? Int { 
      //You can same way access other details of employee, email, etc.. 
      print(company_id) 
      print(department_id) 
    } 
}

來源

2016-12-07 06:28:00

感謝您rply但錯誤在這行 **如果讓味精= convertedJsonIntoDict [ 「味精」]，讓COMPANY_ID =味精[ 「COMPANY_ID」]作爲？ Int， let department_id = msg [「department_id」] as？ Int ** 其顯示類型「任何」沒有下標成員 – johnyDiOS

@johny忘記了添加'as？ [字符串：任何]'檢查編輯的答案。 –

其工作我得到它，並感謝您的教學 – johnyDiOS

如何從字典swift3

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