要獲得RANK相當於你需要得到每個項目的最低指標,當你組:
var ranks = list.OrderBy(x => x)
.Select((x, i) => new {x, i = i+1}) // get 1-based index of each item
.GroupBy(xi => xi.x) // group by the item
.Select(g => new {rank = g.Min(xi => xi.i), items = g}) // rank = min index of group
.SelectMany(g => g.items, (g, gg) => new {g.rank, gg.i}) ; // select rank and item
,或者如果you'rs一類的屬性分組:
var ranks = list.OrderBy(x => x.{some property})
.Select((x, i) => new {x, i = i+1}) // get 1-based index of each item
.GroupBy(xi => xi.x.{some property}) // group by the item's property
.Select(g => new {rank = g.Min(xi => xi.i), items = g}) // rank = min index of group
.SelectMany(g => g.items, (g, gg) => new {g.rank, gg.i}) ; // select rank and item
感謝您的建議。我最終做了與此類似的事情,我很快就會發布我的版本。 – christiandev