1
我有以下XML的XPath從一個表哥節點
<FreightLabelData>
<Consignments>
<Consignment>
<References>
<Reference>
<ReferenceNumber>RefLine1</ReferenceNumber>
<SequenceNumber>1</SequenceNumber>
</Reference>
<Reference>
<ReferenceNumber>RefLine2</ReferenceNumber>
<SequenceNumber>2</SequenceNumber>
</Reference>
</References>
<FreightLabels>
<FreightLabel>
<ReferenceSequenceNumber>1</ReferenceSequenceNumber>
</FreightLabel>
<FreightLabel>
<ReferenceSequenceNumber>2</ReferenceSequenceNumber>
</FreightLabel>
</FreightLabels>
</Consignment>
</Consignments>
</FreightLabelData>
我的XSLT沒有一個for循環,開始爲
<xsl:for-each select="/FreightLabelData/Consignments/Consignment/FreightLabels/*">
對於每個FreightLabel選擇一個值,我需要找到相關的表妹參考文獻/ ReferenceNumber其中FreightLabel/ReferenceSequenceNumber =參考/序列號
我花了相當多的時間尋找答案,沒有任何運氣。有誰知道如何做到這一點?
感謝
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