如何在PHP中設置單選按鈕的值？

Question

如何使用計數器變量或其他選項爲以下PHP代碼中的每個單選按鈕設置名稱？

<?php 

     $id=0; //counter variable 

     $sql ="select roll_number,student_name,gender from student_table"; 
     $query=mysqli_query($dbcon, $sql) or die(mysqli_error($dbcon)); 

      while($post=mysqli_fetch_assoc($query)){ 

      echo '<tr>'; 
      echo '<td>'. $post['roll_number'] . '</td>'; 
      echo '<td>'. $post['student_name'] . '</td>'; 
      echo '<td>'. $post['gender'] . '</td>'; 
      echo '<td width=250>'; 

      echo '<input type="radio" name="rad'.$id'" value="P" />Present'; 
      echo '<input type="radio" name="rad'.$id'" value="A" />Absent'; 

      echo '<button type="submit" name="save" value="Save" class="btn btn-success btn-sm">Save</button>'; 
      ++$id; 
      echo '</td>'; 
      echo '</tr>';    

      } 

      ?> 

Answer 1

echo '<input type="radio" name="rad[' . $post['roll_number'] . ']" value="P" />Present'; 
echo '<input type="radio" name="rad[' . $post['roll_number'] . ']" value="A" />Absent'; 

在你可以做這樣的接收端：

$answers = $_POST['rad']; 
foreach($answers as $roll_number=>$answer){ 
    //do something with the $roll_number and $answer... 
} 

Answer 2

更新的代碼，改變了$post到$row，串聯串，固定<button>等。在任何地方都沒有表格聲明 - 如果你只有一個表格，這可以保存/獲取表格中的每個項目 - 根據你的需要，你可能想要爲每個學生聲明一個表格，並帶有唯一的標識符。

<?php 

$query = mysqli_query($dbcon, 'SELECT roll_number,student_name,gender FROM student_table') or die(mysqli_error($dbcon)); 

while ($row = mysqli_fetch_assoc($query)) { 

    echo '<tr> 
      <td>'.$row['roll_number'].'</td> 
      <td>'.$row['student_name'].'</td> 
      <td>'.$row['gender'].'</td> 
      <td width="250"> 
       <label><input type="radio" name="rad['.$row['roll_number'].']" value="P">Present</label> 
       <label><input type="radio" name="rad['.$row['roll_number'].']" value="A">Absent</label> 
       <input type="submit" name="save" value="Save" class="btn btn-success btn-sm"> 
      </td> 
     </tr>'; 
} 

?>