如何從包含json數組的json對象在angularjs中獲取特定值

我從mysql數據庫中獲取以下數據，其中「comment」來自一個表，「blog」是另一個表。現在我想通過ng-repeat在視圖中顯示這些數據。如何從包含json數組的json對象在angularjs中獲取特定值

{ 
    "comment":[ 
    {"comment_id":"3","blog_id":"1","total_comment":"2"}, 
    {"comment_id":"9","blog_id":"8","total_comment":"3"} 
    ], 
    "blog":[ 
    {"id":"9","title":"jquery","description":"this is about jquery","date":"2016-08-27","status":"active"}, 
    {"id":"8","title":"javascript","description":"this is javascript post","date":"0000-00-00","status":"active"}, 
    {"id":"1","title":"angularjs","description":"this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.","date":"2016-07-12","status":"active"} 
    ] 
}

來源

2016-09-18 shabir ullah

那麼你嘗試過什麼？ – RiggsFolly

{{result.comment.total_comment}} and {{result.blog.title}}

–

我現在已經得到了迴應的數據如何訪問我需要的特定記錄 –

如果相信「blog_id」是博客表和評論表之間的共同字段。

寫聯接查詢在MySQL「ON blog.id = comment.blog_id」，讓你得到你想要的數據，你可能會顯示在響應NG-重複

來源

2016-09-18 12:05:07 Puhal

如何從包含json數組的json對象在angularjs中獲取特定值

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