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我在網上找到了這個示例代碼。它似乎做我想做的事情,向API發出請求,我只需要定製它。Android構造和語法錯誤
然而,當我嘗試編譯它,它給了我同樣的錯誤三線
Syntax error on token(s), misplaced
construct(s)
- Syntax error on token "setEntity", =
expected after this token
也許有些人能看到的東西我沒有?
下面的代碼:
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
public class http {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
}
將引發錯誤的nameValuePairs.add線和httppost.setEntity線
nameValuePairs的錯誤更改通過將「添加」引入錯誤 – GK1667 2012-07-09 16:48:16
的引號中,您的代碼應該位於方法中。請閱讀java教程。 – Ran 2012-07-09 16:49:19