如何創建一個選擇 - 在Zend框架+ MySQL表

Question

選項如何創建一個選擇 - 在Zend框架+ MySQL表選項

控制器：

$persons = new Application_Model_DbTable_Persons(); 
$data_persons = $persons->findPersons(); 

控制器和視圖？如何？ o.O

Answer 1

在控制器

$this->view->dataPerson = $data_persons; 

查看HTML。

foreach($this->dataPerson as $datPers): 
       //Example Get person name. 
      echo $this->escape($datPers->name); 
      and etc. 

endforeach; 

Answer 2

到選擇框中的選項可以被添加作爲使用addMultiOptions()函數數組

$persons = new Application_Model_DbTable_Persons(); 
$data_persons = $persons->findPersons(); 
$data_persons_array = array(); 

foreach($this->dataPerson as $datPers) 
    $data_persons_array[$datPers->id] = $datPers->name 


$name = new Zend_Form_Element_Text('name'); 
$name->setLabel('name') 
     ->setRequired(true) 
     ->addValidator('NotEmpty'); 
     ->addMultiOptions($data_persons_array); //Will add the options to select box