無法從Android中的JSON中將數據導入到PHP webservice中

import android.app.Activity; 
    import android.os.Bundle; 
    import android.os.StrictMode; 
    import android.util.Log; 
    import android.view.View; 
    import android.widget.Button; 
    import android.widget.EditText; 
    import android.widget.Toast; 

    import org.apache.http.HttpResponse; 
    import org.apache.http.client.methods.HttpPost; 
    import org.apache.http.entity.StringEntity; 
    import org.apache.http.impl.client.DefaultHttpClient; 
    import org.apache.http.message.BasicHeader; 
    import org.apache.http.protocol.HTTP; 
    import org.apache.http.util.EntityUtils; 
    import org.json.JSONObject; 


    public class MainActivity extends Activity { 

     @Override 
     protected void onCreate(Bundle savedInstanceState) { 
      super.onCreate(savedInstanceState); 
      setContentView(R.layout.activity_main); 

      if (android.os.Build.VERSION.SDK_INT > 9) { 
       StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build(); 
       StrictMode.setThreadPolicy(policy); 
      } 

      Button btn = (Button) findViewById(R.id.btnInsert); 
      EditText editText = (EditText) findViewById(R.id.editText); 

      final String value = editText.getText().toString(); 

      btn.setOnClickListener(new View.OnClickListener() { 
       @Override 
       public void onClick(View v) { 

        try { 
         JSONObject jsonobj = new JSONObject(); 
         jsonobj.put("name", value); 

         DefaultHttpClient httpclient = new DefaultHttpClient(); 
         HttpPost httppostreq = new HttpPost("http://www.myurl.com/WebserviceInsert2.php"); 

         StringEntity se = new StringEntity(jsonobj.toString()); 

         Log.d("jsonobj is :>", String.valueOf(jsonobj)); 

         se.setContentType("application/json;charset=UTF-8"); 
         se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json;charset=UTF-8")); 

         httppostreq.setEntity(se); 

         HttpResponse httpresponse = httpclient.execute(httppostreq); 

         String responseText = null; 
         try { 
          responseText = EntityUtils.toString(httpresponse.getEntity()); // {"code":1} 
         } catch (Exception e) { 
          e.printStackTrace(); 
          Log.i("Parse Exception", e + ""); 
         } 

         Log.d("Response Text is : ", responseText); 

         JSONObject json = new JSONObject(responseText); 

         int code = json.getInt("code"); 

         if (code == 1) 
          Toast.makeText(getApplicationContext(), "Successful", Toast.LENGTH_LONG).show(); 
         else 
          Toast.makeText(getApplicationContext(), "Fail", Toast.LENGTH_LONG).show(); 
        } catch (Exception e) { 
         Log.d("Error :>", String.valueOf(e)); 
        } 
       } 
      }); 
     } 
    } 



PHP Code: 
<?php 

    include("include/config.php"); 

    $name=$_POST["name"]; 
    //echo $name; 

    $flag['code']=0; 

    if($result=mysql_query("INSERT INTO test (name) VALUES ('".$name."')")) 
    { 
     $flag['code']=1; 
    } 

    print(json_encode($flag)); 

    $obj->close(); 

?>

數據庫表字段「name」爲空。插入查詢成功觸發，但..數據未插入到表中。無法從Android中的JSON中將數據導入到PHP webservice中

我認爲PHP文件沒有得到正確的'名稱'參數從POST應用程序的Android應用程序（JSON）發送的方法。

來源

2015-02-23 Bhavesh Butani

你還沒有公佈實際的logcat的，但你可以試試這個代碼

HttpClient httpClient = new DefaultHttpClient(); 
//Get COding 
HttpPost httpPost = new HttpPost(your_url); 
List<NameValuePair> parameters = new ArrayList<NameValuePair>(); 
parameters.add(new BasicNameValuePair("name", value)); 
//you can add more parameters here 
httpPost.setEntity(new UrlEncodedFormEntity(parameters)); 
HttpResponse httpResponse = httpClient.execute(httpPost); 
HttpEntity httpEntity = httpResponse.getEntity(); 
response=EntityUtils.toString(httpEntity);

您可以添加或設置內容類型或頭平時閱讀更多 http://developer.android.com/reference/org/apache/http/client/HttpClient.html

來源

2015-02-23 11:29:16 rogerwar

因爲您的請求使用該網址，以獲取，方法。如果你發送任何請求到服務器而沒有提到HttpClient會假定GET的請求，但是在你的PHP中你提到了它的$ _POST [「name」];如果你替換= $ _ POST [「name」];與_REQUEST [「name」];

否則，您必須設置請求類型爲Post。

然後數據可能會插入數據庫。

來源

2015-02-23 12:17:17

無法從Android中的JSON中將數據導入到PHP webservice中

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