我是Symfony2的新手,嘗試使用Lexik Filter包;我有兩個實體(家長培訓)以nm(多對多)關係關聯,如下定義,我試圖按名稱過濾父母名單:`tuto \ LexikTestBundle \ Entity \ Parents:Lexik Filter-:參數1傳遞給Symfony Component Form FormRenderer :: searchAndRenderBlock()
type: entity
table: Parents
repositoryClass: tuto\LexikTestBundle\Repository\ParentRepository
id:
id:
type: integer
generator:
strategy: AUTO
fields:
Firstname:
type: string
length: 50
Lastname:
type: string
length: 50
DOB:
type: datetime
Email:
type: string
length: 50
manyToMany:
Trainings:
targetEntity: Training
mappedBy: parents`
我下面的教程與版本3.0.8工作,並定義了以下自定義過濾器類型:
namespace tuto\LexikTestBundle\Form\Filter;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
class MyParentsType extends AbstractType
{
/**
* Returns the name of this type.
*
* @return string The name of this type
*/
public function getName()
{
return 'parents_filter';
}
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('Firstname', 'filter_text');
$builder->add('Lastname', 'filter_text');
}
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(
[
'csrf_protection' => false,
'validation_groups' => ['filtering'] // avoid NotBlank() constraint-related message
]
);
}
}
並在控制器中執行以下FilterAction:
public function indexAction(Request $request)
{
$em = $this->getDoctrine()->getManager();
$entities = $em->getRepository('tutoLexikTestBundle:Parents')->findAll();
$form = $this->testFilterAction($request);
return $this->render('tutoLexikTestBundle:Parents:index.html.twig', [
'entities' => $entities,
'form' => $form,
]
);
}
public function testFilterAction(Request $request)
{
$form= $this->get('form.factory')->create(new MyParentsType());
if($request->query->has($form->getName())) {
// manually bind values from the request
$form->submit($request->query->get($form->getName()));
$queryBuilder = $this->get('doctrine.orm.entity_manager')
->getRepository('LexikTestBundle:Parents')
->createQueryBuilder('e');
//build the query from the given object
$this->get('lexik_form_filter.query_builder_updater')->addFilterConditions($form,$queryBuilder);
var_dump($queryBuilder->getDql());
}
return $this->render(
'tutoLexikTestBundle:Default:testFilter.html.twig',
['form'=>$form->createView()]
);
}
的樹枝實木emented是
<form method="get" action=".">
{{ form_rest(form) }}
<input type="submit" name="submit-filter" value="filter" />
</form>
我已經走線槽以下答案,似乎沒有同樣的錯誤:
但我仍然面對捕致命錯誤:傳遞給Symfony的\分量\形式參數1 \ FormRenderer :: searchAndRenderBlock()必須的Symfony \分量\表格\ FormView控件,實例的實例Symfony \ Component \ HttpFoundation \ Response給出任何提示都會受到歡迎。
我確實試過了,但得到了一個'Ca將未定義的方法Symfony \ Component \ HttpFoundation \ Response :: createView()' –
是的這是預期的行爲,請編輯您的方法如上 – CodeIsLife