我將如何獲得此輸出？

Question

import java.util.Scanner; 
 
public class EuclidGCD { 
 

 
\t public static void main(String[] args) { 
 
\t \t Scanner kbd = new Scanner (System.in); 
 
\t \t System.out.print ("Enter First Number: "); 
 
\t \t int n1 = kbd.nextInt(); 
 
\t \t System.out.print ("Enter Second Number: "); 
 
\t \t int n2 = kbd.nextInt(); 
 
\t \t int gcd = 1; 
 
\t \t int k = 2; 
 
\t \t while (k <= n1 && k <= n2){ 
 
\t \t \t if (n1 % k == 0 && n2 % k == 0) 
 
\t \t \t gcd = k ; 
 
\t \t k ++; 
 
\t \t } 
 
\t \t System.out.println("The GCD of " + n1 + " and " + n2 + " is " + gcd); 
 

 
\t } 
 

 
}

所以一切工作，但我意識到，我不想，如果輸入負數，我想輸出正數，只有這樣我就需要另一個while循環負號是多少？

Answer 1

只需添加一個if語句來檢查n1和n2是否爲正數，如果它們是隻執行了其餘代碼。你不應該需要另一個while循環

public static void main(String[] args) { 
     Scanner kbd = new Scanner (System.in); 
     System.out.print ("Enter First Number: "); 
     int n1 = kbd.nextInt(); 
     System.out.print ("Enter Second Number: "); 
     int n2 = kbd.nextInt(); 
     if(n1 < 0 || n2 < 0){ 
      System.out.println("POSITIVE NUMBERS ONLY "); 

     }else{ 
      int gcd = 1; 
      int k = 2; 
      while (k <= n1 && k <= n2){ 
       if (n1 % k == 0 && n2 % k == 0) 
       gcd = k ; 
      k ++; 
      } 
      System.out.println("The GCD of " + n1 + " and " + n2 + " is " + gcd); 
     } 
    }