用於查詢選擇的內聯用戶數據輸入操作| Python

Question

我正在開發一個允許用戶輸入查詢的Python故障排除應用程序。此查詢將包含設備的品牌以及問題的症狀或問題。我正在編寫一個腳本，它基本上對查詢進行剖析，以便根據設備的關鍵字和品牌找到適當的解決方案。

目前代碼： #IMPORT模塊 進口警告

#Define Globals 
brands = ["apple", "android", "windows"] 
brand = '' 

def Main(): 
    init() 
    print("--Welcome to Troubleshooting Applet--") 
    print("In your query please include the brand of your device and the problem/symptom of your current issue. \n") 
    query = input("Enter your query: ").lower() 
    brand = set(brands).intersection(query.split()) 
    if brand != '': 
     print(brand) 
    else: 
     print("Brand in existance not defined") 

def init(): 
    #warnings.filterwarnings("ignore") #Disable while debugging 

if __name__ == '__main__': 
    Main() 

目前，該腳本將確定一個品牌，但我不如何才能跟隨檢查寬一些關鍵字一定解決途徑。我希望解決方案能夠按照選擇一個品牌的特定品牌的次要陣列的模式，其中包含一些潛在的錯誤。每個錯誤都可以定義一個解決方案。

我將不勝感激任何見解，

感謝，

山姆

Answer 1

運行此我希望這給你一些想法。您需要修復main():函數的縮進。

#Define Globals 
brands = ["apple", "android", "windows"] 
brand = '' 
import random 
def Main(): 
     init() 
     print("--Welcome to Troubleshooting Applet--") 
     print("In your query please include the brand of your device and the problem/symptom of your current issue. \n") 
     query = input("Enter your query: ").lower() 
     brand = set(brands).intersection(query.split()) 
     keywords = ['custom security keywords collection', 'item2', 'key3'] 
     index = 0 
     for i in range(len(query)): 
      if query.__contains__(keywords[index]): # __iter__() # could use 'in' keyword here 
       #switch/decide 
       text = 'run decision' 
       print(keywords[index]) 
      else: 
       if len(keywords) < 3: 
        index = index + 1 
       text1 = 'continue' 
     # OR 
     # Test keyword idea... 
     tKeyword = random.choice(keywords) 
     # You need a lot of work to come up with error decisions right? 
     # You may need to start pulling from a Database and checking against large documents? 
     # just trying to come up with something to get you going 
     print ('RANDOM keyword for TESTING:' + tKeyword) 
     if brand != '': 
      print(brand) 
     else: 
      print("Brand in existance not defined") 

def init(): 
     ftp = 0 
    #warnings.filterwarnings("ignore") #Disable while debugging 

if __name__ == '__main__': 
    Main() 
    print('ask yourself about escape sequences and encoding for the query? \+' 
      ' I believe utf-8 is the default encoding for python 3') 

def dbconnect(): 
    url = "http://stackoverflow.com/questions/372885/how-do-i-connect-to-a-mysql-database-in-python" 
    url1 = "https://docs.python.org/3/reference/datamodel.html#object.__contains__" 
    url2 = "مرحبا I think python is very unicode friendly.."