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嗨有人知道爲什麼我的「button1」不顯示?我似乎無法弄清楚,當我執行該程序它一切正常,運行成功,但它不顯示此按鈕。任何幫助,將不勝感激。JButton不顯示
private Container c;
private JPanel gridPanel;
private JComboBox combo;
final JLabel label = new JLabel();
private JButton button1 = new JButton("Clear");
private JButton button2 = new JButton("Exit");
/**
* Christopher Haddad - 559815X
*/
public Planets() {
c = getContentPane();
gridPanel = new JPanel();
gridPanel.setLayout(new GridLayout(5, 0, 0, 0));
label.setVisible(true);
combo = new JComboBox();
combo.setEditable(false);
combo.addItem("No Planet Selected");
combo.addItem("Mercury");
combo.addItem("Venus");
combo.addItem("Earth");
gridPanel.add(combo);
add(button1);
add(button2);
button1.addActionListener(this);
button2.addActionListener(this);
c.add(gridPanel, BorderLayout.NORTH);
setTitle("Planet Diameter");
setSize(700, 250);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setVisible(true);
combo.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent event) {
JComboBox comboBox = (JComboBox) event.getSource();
Object select = comboBox.getSelectedItem();
if(select.toString().equals("No Planet Selected"))
label.setText("");
else if(select.toString().equals("Mercury"))
label.setText("The planet Mercury is 3100kms in diameter");
else if(select.toString().equals("Venus"))
label.setText("The planet Venus is 7500kms in diameter");
else if (select.toString().equals("Earth"))
label.setText("The planet Earth is 8000kms in diameter");
}
});
getContentPane().add(combo);
getContentPane().add(label);
}
// event handling method, implementing the actionPerformed method of ActionListener
public void actionPerformed(ActionEvent e)
{
// set the button label to number of times it has been clicked
if(e.getSource() == button1) {
label.setText(" ");
}
else if(e.getSource() == button2) {
System.exit(0);
}
}
沒關係,解決它,謝謝 – thechrishaddad
這是導致你的佈局,刪除帖子,然後的xD – nachokk
IIRC只有主持人可以刪除帖子。 – mattbdean