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我想一個IRQ處理程序附加到GPIO銀行0即0B irq no 97
。InterruptAttach上am3352x IRQ號97失敗銀行0B
在目前,我的執行返回-1
。我究竟做錯了什麼?這將是一個非常簡單的問題。
#include <stdio.h>
#include <unistd.h>
#include "gpio.h"
#include <sys/neutrino.h>
#include "interrupt.h"
volatile unsigned int gpio0_irq_count;
static const struct sigevent * gpio0_irq_handler (void *gpio, int id){
gpio0_irq_count++;
return NULL;
}
int main(){
int ret;
unsigned long count=0;
ret = InterruptAttach(97, gpio0_irq_handler, NULL,0,_NTO_INTR_FLAGS_TRK_MSK);
printf("%s: Registering handler for irq %d result = %d\n",__func__ , 97, ret);
if (ret)
return -1;
while(1){
printf("%s:[%lu] : gpio0_irq_count = %d\n", __func__, count++, gpio0_irq_count);
sleep(2);
}
}
的錯誤的輸出是:
main: Registering handler for irq 97 result = -1