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我試圖在搜索參數去使用結果從選擇如何使用類似參數的選擇?
SELECT distinct policy_business_unit_id as number FROM `policies` WHERE (policy_business_unit_id ='2')
這個條件顯示
number
2
我想在我的PARAM狀態下使用「2」。
SELECT distinct policy_business_unit_id as number FROM `policies` WHERE (policy_business_unit_id ='2')
SELECT * FROM `cia_ensures` WHERE (id = 2)
,但我發現這個
SELECT * FROM `cia_ensures` WHERE (id = NULL)
我的表:
|cia_ensures|
|id| |name|
1 aaa
2 bbb
3 ccc
...
|policy_business_units|
|id| |name|
1 abc
2 def
3 ghi
...
|policies|
|id| |number| |policy_business_unit_id|
1 1234 2
2 5678 1
3 9123 2
4 4567 1
...
這裏是控制器:
def ajax
@business = PolicyBusinessUnit.find(:all)
@select = Policy.find(:all,:select=>['distinct policy_business_unit_id as number'],:conditions=>['policy_business_unit_id = ?',params[:business] ])
@list_cias = CiaEnsure.find(:all,:conditions=>['id = ?',@select])
end
這裏是模型:
class Policy < ActiveRecord::Base
belongs_to :cia_ensure
end
class CiaEnsure < ActiveRecord::Base
has_many :policies
end
這裏是視圖:
Business:
<%= select_tag "business",options_for_select(@list_cias.collect {|t| [t.name.to_s ,t.id]}, params[:business].to_i) %>
Cias:
<%= select_tag "cias",options_for_select(@business.collect {|t| [t.name.to_s ,t.id]}, params[:cias].to_i) %>
我試圖做的是:
@business = PolicyBusinessUnit.find(:all)
@select = Policy.find(:all,:select=>['distinct policy_business_unit_id as number'],:conditions=>['policy_business_unit_id = ?',params[:business] ])
@list_cias = CiaEnsure.find(:all,:conditions=>['id = ?',@select[0].try(:number) ])
這裏是我的日誌:
##### HERE I SHOULD HAVE THE NUMBER 2
SELECT distinct policy_business_unit_id FROM `policies` WHERE (policy_business_unit_id ='2')
##### I WANT TO USE NUMBER 2
SELECT * FROM `cia_ensures` WHERE (id = NULL)
請有人可以幫助我?
感謝的人,當我試圖不工作,但我重新啓動我的控制檯,現在正在工作。 =) 謝謝。 –