MySQL的合併具體的行

Question

當前表：

╔════════════════════════════════════════╗ 
║ id ║ price ║ tax ║ sku ║ description ║ 
╠════════════════════════════════════════╣ 
║ 123 ║ 10 ║ 1 ║ sku1 ║ Dress  ║ 
║ 123 ║ 0  ║ 0 ║ sku1 ║ Dress-Small ║ 
╚════════════════════════════════════════╝ 

結果，我想：

╔════════════════════════════════════════════╗ 
║ id ║ price ║ tax ║ sku ║ description ║ 
╠════════════════════════════════════════════╣ 
║ 123 ║ 10  ║ 1 ║ sku1 ║ Dress-Small ║ 
╚════════════════════════════════════════════╝ 

我想ID，價格，稅和SKU從第一排，然後從第二排獲取說明。這怎麼能實現？

Answer 1

如何

SELECT MAX(id) id, 
      MAX(price) price, 
      MAX(tax) tax, 
      sku1, 
      MAX(description) description 
     FROM Table 
    GROUP BY sku1 

你沒有解釋你如何知道第二行包含正確的描述，所以這是一個猜測。

Answer 2

這是你的答案。例如SQL Fiddle

SELECT A.id, A.price, A.tax, A.sku, B.Description 
FROM (
    SELECT * 
    FROM MyTable 
    WHERE description = 'Dress' 
) AS A 
LEFT JOIN (
    SELECT * 
    FROM MyTable 
    WHERE description = 'Dress-Small' 
) AS B 
ON A.ID = B.ID 

我會考慮在什麼id柱確實爲你的餐桌很難看。不妨將它刪除。