比較像MySQL

Question

文字字符我有這個表：

 
|--------------------------|------------------| 
|  tab1    |  tab2   | 
|--------------------------|------------------| 
| Guerreo Reyna   |   1  | 
|--------------------------|------------------| 
| Marroquin Bocanegra  |   10  | 
|--------------------------|------------------| 
| Calderon Salguero  |   10  | 
|--------------------------|------------------| 
| De la Cruz Barrios  | 1,2,3,4  | 
|--------------------------|------------------| 
| Guillen Cornet   |  1,3  | 
|--------------------------|------------------| 
| Luna Mendiví    |   10  | 
|--------------------------|------------------| 
| Chang Ruiz    |   1  | 
|--------------------------|------------------| 

當我做這個查詢：

SELECT DISTINCT f.familias, 
       f.apellidos, 
       i.nombre 
FROM familias AS f 
INNER JOIN integrantes AS i ON f.familias = i.familia 
WHERE tab2 LIKE '%1%' 
    OR tab2 LIKE '%3%' 
ORDER BY 1 

我只需要恢復那些誰擁有1和3，而不是10

非常感謝你

Answer 1

SELECT DISTINCT f.familias, 
       f.apellidos, 
       i.nombre 
FROM familias AS f 
INNER JOIN integrantes AS i ON f.familias = i.familia 
WHERE find_in_set('1',`tab2`) and find_in_set('3',`tab2`) 
ORDER BY 1 

Answer 2

WHERE concat(',', tab2, ',') LIKE '%,1,%' 
    OR concat(',', tab2, ',') LIKE '%,3,%' 
ORDER BY 1