我正在寫一個認證系統與移動jQuery和PHP。 html代碼如下:Jquery手機+ PHP認證系統
<div data-role = "page" id ="dialogo">
<a href = "#identificacion" id = "formdialog" data-rel="dialog"> </a>
</div>
<div data-role = "page" id = "identificacion">
<div id ="main">
<div id ="caplogin">
<img src = "images/vives_logo.png"/>
<p> Acceso Promoción Vives </p>
<div style ="clear:both;"></div>
</div>
<div style ="clear:both;"></div>
<div id ="formlogin">
<form name ="formautentificacion" id ="formautentificacion" method = "post" action = "" data-ajax="false">
<table>
<tr> <td> Login </td> <td> <input type ="text" name ="user" id ="user" size="30"/></td> </tr>
<tr> <td> Password </td><td><input type ="password" name ="pass" id="pass" size="30"/></td></tr>
<tr> <td colspan = "2" align ="right"> <input type = "submit" id = "sbmt_aut" name = "sbmt_aut" value = "ENTRAR"/></td>
</table>
</form>
</div>
</div>
</div>
<div data-role = "page" id = "pageclients">
<div id = "headerpageclient">
<a href="index.php" class ="logout" data-role="button" data-icon="delete">SALIR</a>
</div>
<div id = "clientes">
</div>
</div>
<div data-role = "page" id = "pagepuntosventa">
<div id = "headerpagepuntoventa">
</div>
</div>
我有兩個AJAX功能與Ajax響應,根據它來啓動和破壞PHP會話,並使用changepage,登錄的功能是正確的,註銷,但Safari瀏覽器後退按鈕不工作,並落在最後一頁。
$(document).delegate("#dialogo", "pageinit", function() {
$("#formdialog").click();
})
$(document).delegate("#identificacion", "pageinit", function() {
$("#formautentificacion").submit(function(e){
e.preventDefault();
//e.stopImmediatePropagation();
$.ajax({
type: 'POST',
url: 'ax/login.php',
data:$(this).serialize(),
cache: false,
success: function(data)
{
if(data == 1)
{
//$.mobile.changePage("promocion.php", {transition: "flip"});
//window.location = "index.php";
$.mobile.changePage("#pageclients", {transition: "flip"});
}
else
{
if (data == 2)
alert("Usuario bloqueado, 3 intentos fallidos");
else
alert("Error en la identificación");
}
$("#user").val("");
$("#pass").val("");
}
})
})
$(".logout").click(function(e){
//e.preventDefault();
logout();
})
})
$(document).delegate("#pageclients", "pageinit", function() {
seguridad();
})
功能SEGURIDAD()進行檢查的會話是:
session_start();
include("../class/aut.php");
$aut = new aut();
$res = 0;
if (!empty($_SESSION["usuario"]) && !empty($_SESSION["token"]))
{
$_SESSION["usuario"] = mysql_real_escape_string($_SESSION["usuario"]);
$_SESSION["token"] = mysql_real_escape_string($_SESSION["token"]);
if ($aut->checktoken($_SESSION["usuario"],$_SESSION["token"]))
{
$_SESSION["token"] = md5(rand().$_SESSION["usuario"]);
$aut->updateToken($_SESSION["usuario"], $_SESSION["token"]);
$res = 1;
}
else
{
session_destroy();
session_unset();
$res = 0;
//header("Location: index.php");
//exit;
}
}
else
{
session_destroy();
session_unset();
$res = 0;
//header("Location: index.php");
//exit;
}
echo $res;
?>
和功能註銷:
function logout()
{
$.ajax({
type: 'GET',
url: 'ax/logout.php',
cache:false,
//async: false,
success: function(data)
{
$("#formdialog").click();
}
})
}
我嘗試關閉會話,然後用安全每一頁上函數來驗證會話。但是一旦摧毀了會議,我可以回到一個頁面而不是跳過對話。
任何想法?
$ .mobile.changePage無法成功成功ajax函數,如果html文件是多頁,我如何使用remove()方法的頁面,第一頁#dialogo,我不應該刪除,因爲是第一頁。 現在,我不知道爲什麼當按下後退按鈕執行與URL index.php(這是運行jquery get並不知道爲什麼)獲取ajax。 所有這一切,功能是正確的 – vllopico