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我需要能夠按類別名稱組織我的JSON。我通過Category ID(項目)和Key(類別)將兩個錶鏈接在一起。我希望能夠將所有帶有類別ID標記的項目組織在類別表的類別名稱下。這是我到目前爲止的代碼:PHP MySQL JSON按數據組織
$query = "SELECT * FROM items,category WHERE items.category_id = category.key";
$result = mysql_query($query,$link) or die('Errant query: '.$query);
while($row = mysql_fetch_array($result))
extract($row);
$channel['items'][] = array(
'title' => $title,
'category_id' => $category_id,
'category_name' => $category_name,
'category_key' => $key,
);
}
$channels = array($channel);
$json = json_encode($channel);
header('Content-type: application/json');
echo $json;
}
它輸出JSON是這樣的:
{
"items": [
{
"title": "putting in title",
"category_id": "7",
"category_name": "Stuff 1",
"category_key": "7"
},
{
"title": "another title",
"category_id": "7",
"category_name": "Stuff 1",
"category_key": "7"
},
但我需要的JSON通過類別名稱進行組織,就像這樣:
{
"Stuff 1": [
{
"title": "putting in title",
"category_id": "7",
"category_name": "Stuff 1",
"category_key": "7"
},
{
"title": "another title",
"category_id": "7",
"category_name": "Stuff 1",
"category_key": "7"
},
"Stuff 2": [
{
"title": "putting in title",
"category_id": "7",
"category_name": "Stuff 2",
"category_key": "7"
},
{
"title": "another title",
"category_id": "7",
"category_name": "Stuff 2",
"category_key": "7"
},
任何幫助完成這一點將不勝感激!
OMG!這太容易了!我很尷尬。謝謝Lauri。如果我需要將所有內容都放入項目數組中,該怎麼辦?我該怎麼辦? – mreynol
你的意思是'$ channel ['items'] [$ category_name]'? –
完美。非常感謝Lauri! – mreynol