獲取的XPath名從.asp網頁的HTML元素

Question

我需要刮這個HTML頁面...

http://www.asl1.liguria.it/templateProntoSoccorso.asp

....使用PHP和XPath來獲取值一樣2

Codice比安科：

（注：你可以看到不同的價值如果你嘗試瀏覽它...沒關係......，他們改變dinamically ....）

我無法獲得XPath這些值使用Mozilla Firebug通常我做：有什麼建議？

預先感謝您！

UPDATE

<?php 
    ini_set('display_errors', 1); 

    $url = 'http://www.asl1.liguria.it/templateProntoSoccorso.asp'; 

    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_AUTOREFERER, TRUE); 
    curl_setopt($ch, CURLOPT_HEADER, 0); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
    curl_setopt($ch, CURLOPT_URL, $url); 
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE); 
    curl_setopt($ch, CURLOPT_PROXY, ''); 
    $data = curl_exec($ch); 
    curl_close($ch); 

    $dom = new DOMDocument(); 
    @$dom->loadHTML($data); 

    $xpath = new DOMXPath($dom); 

    $Number = $xpath->query('/html/body/table/tbody/tr/td[2]/table[2]/tbody/tr/td[3]/table/tbody/tr[2]/td[1]/table/tbody/tr/td/div[1]/div[3]/div[2]'); 

    foreach($Number as $node) 
    { 
     echo "Number: " .$node->nodeValue; 
     echo '<br>'; 
     echo '<br>'; 
    }  
?> 

Answer 1

我解決下一個值...這裏你是正確的代碼

<?php 
    ini_set('display_errors', 1); 

    $url = 'http://www.asl1.liguria.it/templateProntoSoccorso.asp'; 

    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_AUTOREFERER, TRUE); 
    curl_setopt($ch, CURLOPT_HEADER, 0); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
    curl_setopt($ch, CURLOPT_URL, $url); 
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE); 
    curl_setopt($ch, CURLOPT_PROXY, ''); 
    $data = curl_exec($ch); 
    curl_close($ch); 

    $dom = new DOMDocument(); 
    @$dom->loadHTML($data); 

    $xpath = new DOMXPath($dom); 

    $Number = $xpath->query('(//div[@class="datiOspedaleCodici"]/div[1]/text())[1]'); 

    foreach($Number as $node) 
    { 
     echo "Number: " .$node->nodeValue; 
     echo '<br>'; 
     echo '<br>'; 
    }  
?> 

的打印...

Codice bianco：2

Answer 2

這應該工作：

1. 值從第一個元素：

   substring-after(//div[@class="datiOspedaleCodici"]/div[1]/text(), ":") 
   

2. 從第二：

   substring-after(//div[@class="datiOspedaleCodici"]/div[2]/text(), ":") 
   

   ...等

只是增加/div[x]指數得到