C#代碼: //這裏我試圖在我的表中插入值。我在命令執行過程中遇到致命錯誤
case true:
Connection.Connect();
int fk_pic = IdPic();
string insertWork = "INSERT INTO work (fk_id_pic, fk_login, university, lesson, name, info, date_work, price) VALUES (@fk_pic, @fk_login, @university, @lesson, @name, @info, @date_work, @price); Allow User Variables = true;";
MySqlCommand work = new MySqlCommand(insertWork, Connection.Connect());
work.Parameters.AddWithValue("@fk_pic", fk_pic);
work.Parameters.AddWithValue("@fk_login", Program.form1.login);
work.Parameters.AddWithValue("@university", textBox1.Text);
work.Parameters.AddWithValue("@lesson", textBox2.Text);
work.Parameters.AddWithValue("@name", textBox3.Text);
work.Parameters.AddWithValue("@info", richTextBox1.Text);
work.Parameters.AddWithValue("@date_work", DateTime.Now);
work.Parameters.AddWithValue("@ price", textBox4.Text);
work.ExecuteNonQuery();
Connection.Disconnect();
break;
SQL查詢:
CREATE TABLE pic
(
id_pic INTEGER UNSIGNED NOT NULL AUTO_INCREMENT COMMENT 'id of image',
caption CHAR(45) NOT NULL COMMENT 'the name of image',
who_add CHAR(30) NOT NULL COMMENT 'who add this image',
img LONGBLOB NOT NULL,
CONSTRAINT pkId_pic PRIMARY KEY(id_pic)
)
COMMENT 'Table for hosting images';
不知道該怎麼辦。等待響應)
什麼是錯誤? –
您可以發佈錯誤的詳細信息 - 例如異常消息嗎? –
「work.Parameters.AddWithValue(」@ price「,textBox4.Text);」 - 可能不應該是「@」後面的空格 –