PHP變量的作用域幫助

Question

require_once('classes/class.validation.php'); 

$array = $_POST['array']; 
$pass_profanity = false; 
$validation = new Validation; 
function check_for_profanity($input){ 
    if(is_array($input)){ 
     foreach($input as $row){ 
      if(is_array($row)){ 
       check_for_profanity($input); 
      } else { 
       $pass_profanity = $validation->check_for_profanity($row); 
      } 
     } 
    } else { 
     $pass_profanity = $validation->check_for_profanity($input); 
     return; 
    } 
    return; 
} 
check_for_profanity($array); 

但我得到的錯誤：

Notice: Undefined variable: validation in /Library/WebServer/Documents/file.php on line 22

Fatal error: Call to a member function check_for_profanity() on a non-object in /Library/WebServer/Documents/file.php on line 2

我不出來，有什麼想法？？？

在此先感謝！

Answer 1

您可以訪問該變量在功能與global：

function check_for_profanity($input){ 
    global $validation; 
    ... 
} 

或者，更好的方式是通過檢索它參數：

function check_for_profanity($input, $validation){ 
    ... 
} 

check_for_profanity($array, $validation); 

R ead the PHP manual - variable scope for more information

Answer 2

您正在定義$ validation = new Validation;功能之外。因此PHP不知道它存在。

Answer 3

使用global關鍵字：PHP.net: Variable Scope

$validation = new Validation; 
function check_for_profanity($input){ 

    global $validation; 

    //The rest of your function 
}