按字母順序排列JSON數據

我一直在嘗試從按照字母順序輸入/輸入到HTML文檔的JSON文檔中獲取數據。我發現堆棧溢出的類似請求;但是，在實現當前代碼的解決方案時，JSON數據不會根據需要進行重組。按字母順序排列JSON數據

當前的代碼：

$(document).ready(function() { 

    //Content Viewer Information 
    function checkViewers() { 
    //Base Variables 
    var viewer = $('#viewed span.user'); 
    var totalViews = $('#viewed span.user').length; 
    var shortenViews = $('#viewed span.user').length -1; 

    if (totalViews === 0) { 
     $('<span> 0 people have </span>').insertBefore($('#viewed span:last-child')); 
    } 
    if (totalViews === 2) { 
     $('<span> and </span>').insertAfter(viewer.first()); 
    } 
    if (totalViews >= 3) { 
     viewer.slice(1).hide(); 
     $('<span> and </span>').insertAfter(viewer.first()); 
     $('<span class="user count"></span>').insertAfter(viewer.eq(2)); 
     $('.count').html(shortenViews + ' more people'); 
    } 
    } 

    //JSON Data 
    var xhr = new XMLHttpRequest(); 

    //Sort Alphabetically 
    function SortAlphabetically(a, b) { 
     a = a.toLowerCase(); 
     b = b.toLowerCase(); 

     return (a < b) ? -1 : (a > b) ? 1 : 0; 
    } 

    xhr.onload = function() { 
     if (xhr.status === 200) { 
      responseObject = JSON.parse(xhr.responseText); 

      var newViewers = ''; 
      for (var i = 0; i < responseObject.profiles.length; i++) { 
       newViewers += '<span class="user">' + responseObject.profiles[i].firstName + ' '; 
       newViewers += responseObject.profiles[i].lastName + '</span>'; 
       newViewers += ' '; 
      } 

      responseObject.profiles.sort(function(a, b) { 
       return SortAlphabetically(a.firstName, b.firstName);  
      }); 
      console.log('JSON Sorted'); 

      //Update Page With New Content 
      var viewerSection = $('#viewed'); 
      viewerSection.html(newViewers); 

     } 
    }; 

    xhr.open('GET', 'data.json', true); 
    xhr.send(null); 

    checkViewers(); 

});

我不知道該解決方案將是對這一問題的是什麼，或者是否有可能是一個更好的方向與按字母順序排序JSON數據去。任何意見或幫助表示讚賞。

查看當前的代碼和示例Plunker。

來源

2015-01-04 Andrew

您可以張貼了一下JSON對象？像responsObject.profiles數組？ –

你排序後您構建HTML數據。移動呼叫responseObject.profiles.sort的for以上循環：

//excerpt from the code you provided 
    //See the plunk for full code 
    xhr.onload = function() { 
     if (xhr.status === 200) { 
      responseObject = JSON.parse(xhr.responseText); 
      //SORT BEFORE GENERATING HTML 
      responseObject.profiles.sort(function(a, b) { 
       return SortAlphabetically(a.firstName, b.firstName);  
      }); 
      console.log('JSON Sorted');   
      var newViewers = ''; 
      for (var i = 0; i < responseObject.profiles.length; i++) { 
       newViewers += '<span class="user">' + responseObject.profiles[i].firstName + ' '; 
       newViewers += responseObject.profiles[i].lastName + '</span>'; 
       newViewers += ' '; 
      } 
     //End of excerpt

Plunker：http://plnkr.co/edit/aW1rpiwu6OHiZj8QXA6D?p=preview

來源

2015-01-04 01:22:06

var objectArrayList = [{x:1,y:"Gazi"},{x:1,y:"Ahmet"},{x:1,y:"Fatih"},{x:1,y:"Ertuğrul"}]; 
 
objectArrayList .sort(function(x1,x2){return x1.y>x2.y;}); 
 
$(objectArrayList).each(function(x){ 
 
$("body").append(this.y+"<br>"); 
 
}); 
 
$("body").append("<b>REVERSE</b><br>"); 
 
var objectArrayList = [{x:1,y:"Gazi"},{x:1,y:"Ahmet"},{x:1,y:"Fatih"},{x:1,y:"Ertuğrul"}]; 
 
objectArrayList .sort(function(x1,x2){return x1.y<x2.y;}); 
 
$(objectArrayList).each(function(x){ 
 
$("body").append(this.y+"<br>"); 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<body></body>

來源

2015-01-04 01:21:50

按字母順序排列JSON數據

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