獲取未禁用的下一個對象ID

Question

目前的問題是我改變了從awnser得到的功能，但之前的功能無效。

function getPrev(currPhotoId) { 
    var i = currPhotoId - 1; 
    i %= album.length; 
    while (album[i].disabled) { 
     i--; 
     i %= album.length; 
    } 
    return i; 
} 

輸出工作，只要是大於0

TypeError: album[i] is undefined 
undefined = "0" 
while (album[i].disabled) 

Answer 1

以下邏輯非常簡單。訣竅是繼續迭代，直到找到一個未禁用的模式，使用模數（%）執行循環操作，直到達到最終結果。

function getNext() { 
    var i = this.currPhotoId + 1; 
    i %= this.album.length; 
    while (this.album[i].disabled) { 
     i++; 
     i %= this.album.length; 
    } 
    return this.album[i]; 
} 

function getPrev() { 
    var i = this.currPhotoId - 1; 
    i %= this.album.length; 
    while (this.album[i].disabled) { 
     i--; 
     i %= this.album.length; 
    } 
    return this.album[i]; 
} 

只要確保有至少一個啓用了或此將無限循環。 :)

Answer 2

function removeImage(element, event){ 
    var albumHolder = document.getElementById('album'); 
    albumHolder.removeChild(element); 
    event.preventDefault(); 
    currPhotoId = element.id.split("_"); 

    // This should be a bit simpler 
    album[currPhotoId].disabled = true; 
    console.log(album); 
} 

然後...

function disabledCheck(currentID, direction) 
if(album[currentID].disabled){ 
    // search for next one which isn't disabled in next or previous direction 
}else{ 
    return currentID 
} 

，如果你想跳過這個元素，並搜索下一個沒有-disabled one

function disabledCheck(currentID, direction) 
for(var i = 0; i < (album.length - currentID)) 
{ 
    if(album[currentID].disabled){ 
     // search for next one which isn't disabled in next or previous direction 
     continue; 
    }else{ 
     return currentID 
    } 
    i++; 
}