如何在文件解壓縮嵌套循環：Python的

Question

輸入示例：

Blank {Line0} 
Loop 3 {Line1} 
Blank {Line1a} 
Label2: Blank {Line2} 
Blank {Line3} 
Loop 2 {Line4} 
Blank {Line4a}  
Label1: Blank {Line5}  # I need to repeat the Jump statements as many times as mentioned in the Loop before the Label statement. Always The Loop statements precedes the immediate Jump statement. So here Line5, Lin6 and Line7 gets repeated twice. Jump to label1 so print line5, Line6 (since it has nothign going on) and Line7 is the end of Jump statement. Repeat it twice. Since Loop 2 {Line4} says do the following Jump Twice. 
Blank {Line6} 
Jump Label1 {Line7} 
Blank {Line8} 
Jump Label2 {Line9} # This jumps back to Label2. Which repeats everything until this line including the expanded inner loop ... This is the nested loop. 
Blank {Line10} 

輸出例：

Line0 
Line1 
Line1a 
Line2 
Line3 
Line4 
Line4a 
Line5 
Line6 
Line7 
Line5 
Line6 
Line7 
Line8 
Line9 
Line2 
Line3 
Line4 
Line4a 
Line5 
Line6 
Line7 
Line5 
Line6 
Line7 
Line8 
Line9 
Line2 
Line3 
Line4 
Line4a 
Line5 
Line6 
Line7 
Line5 
Line6 
Line7 
Line8 
Line9 
Line10 

我現在有，對於在文件中循環和重複循環工作的代碼。但打破上面給出的輸入文件。我嘗試從這裏實現@Samy Arous方法：Using Python to Parse a File for Nested Loops但無法實現它。爲了清晰起見，將其作爲一個單獨的問題提出。

所有的行只是字符串...這是一個有點複雜的格式，所以只是給了一個簡單的。我們可以假設Blank，JUMP，LOOP都指導着需要完成的事情。無論是剛剛打印出來或重複基於循環和跳轉

我的代碼：

import sys 

inputtfile = sys.stdin 
inputfileContents = open(r'path to input file') 


def extract(line): 
    return line[line.find('{') + 1: line.rfind('}')] 

loopCount = 0 
loopLines = [] 
inLoop = False 
for line in inputfileContents: 
    if line.startswith('Loop '): 
     loopCount = int(line.split()[1]) 
     inLoop = True 
    elif line.startswith('Jump '): 
     loopLines.append(extract(line)) 
     for i in range(loopCount): 
      for loopLine in loopLines: 
       print loopLine 

#reset state variables to track next possible loop 
     loopCount = 0 
     inLoop = False 
     loopLines = [] 
    elif inLoop: 
     loopLines.append(extract(line)) 
    else: 
     print extract(line) 

Answer 1

確定好，如果輸入的文件是不是你的，那麼你不能做與可怕的格式。我認爲處理嵌套最簡單的方法是使用遞歸函數。

約怪異的輸入格式一些假設：

• 的「環行」永遠啓動的「循環」的下一行。
• 我忽略了標籤。對於「跳」，只是意味着「結束循環」

反正輸出我得到的都是符合您的預期，但如果我的假設是不正確的，你需要對此進行修改。

with open(r'path to input file') as f: 
    inputfileContents = f.readlines() 

def printLines(lines): 
    nest_level = 0 
    for i, line in enumerate(lines): 
     print line.split('{')[-1].split('}')[0] 
     if line.startswith('Jump '): 
      nest_level -= 1 
      if nest_level < 0: 
       return 
     elif line.startswith('Loop '): 
      nest_level += 1 
      loopCount = int(line.split()[1])-1 
      for cnt in range(loopCount): 
       printLines(lines[i+1:]) 

printLines(inputfileContents) 

編輯 - >下面是跳轉到標籤，而不是修改後的版本。適用於當前的示例輸入，但有很多方法可能會導致輸入錯誤。

with open(r'path to input file') as f: 
    inputfileContents = f.readlines() 

def printLines(lines): 
    loop_cnt = [] 
    label_to_idx = {} 
    for i, line in enumerate(lines): 
     line = line.split('#')[0] #removing comments 
     print line.split('{')[-1].split('}')[0] 
     line_label = line.split('{')[0].strip() 
     line_label = line_label.replace(':','') #I assume the colon is a typo? 
     label_to_idx[line_label] = i 

     if line.startswith('Jump '): 
      if not loop_cnt: 
       return 
      jump_label = line.split()[1] 
      start = label_to_idx[jump_label] 
      loopCount = loop_cnt.pop() 
      for cnt in range(loopCount): 
       printLines(lines[start:]) 
     elif line.startswith('Loop '): 
      loopCount = int(line.split()[1])-1 
      loop_cnt.append(loopCount) 

printLines(inputfileContents)