請忽略我的經驗不足,因爲這使用這個,非常新的編碼是第一次,但我不斷收到此錯誤:android.database.sqlite:SQLiteException:沒有這樣的表存在錯誤持續出現
「所致。 SQLiteException:沒有這樣的表:照片(代碼1):,編譯時:SELECT * FROM照片)「
請幫忙!
import java.util.ArrayList;
import java.util.HashMap;
import android.util.Log;
import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
public class DBController extends SQLiteOpenHelper {
private static final String LOGCAT = null;
public DBController(Context applicationcontext) {
super(applicationcontext, "androidsqlite.db", null, 1);
Log.d(LOGCAT,"Created");
}
@Override
public void onCreate(SQLiteDatabase database) {
String query;
query = "CREATE TABLE photo (photoId INTEGER PRIMARY KEY, photoName TEXT)";
database.execSQL(query);
Log.d(LOGCAT,"photo Created");
}
@Override
public void onUpgrade(SQLiteDatabase database, int version_old, int current_version) {
String query;
query = "DROP TABLE IF EXISTS photo";
database.execSQL(query);
onCreate(database);
}
public void insertPhoto (HashMap<String, String> queryValues) {
SQLiteDatabase database = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put("photoName", queryValues.get("photoName"));
database.insert("photo", null, values);
database.close();
}
public int updatePhoto (HashMap<String, String> queryValues) {
SQLiteDatabase database = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put("photoName", queryValues.get("photoName"));
return database.update("photo", values, "photoId" + " = ?", new String[] { queryValues.get("photoId") });
//String updateQuery = "Update words set txtWord='"+word+"' where txtWord='"+ oldWord +"'";
//Log.d(LOGCAT,updateQuery);
//database.rawQuery(updateQuery, null);
//return database.update("words", values, "txtWord = ?", new String[] { word });
}
public void deletePhoto(String id) {
Log.d(LOGCAT,"delete");
SQLiteDatabase database = this.getWritableDatabase();
String deleteQuery = "DELETE FROM photo where photoId='"+ id +"'";
Log.d("query",deleteQuery);
database.execSQL(deleteQuery);
}
public ArrayList<HashMap<String, String>> getAllPhoto() {
ArrayList<HashMap<String, String>> wordList;
wordList = new ArrayList<HashMap<String, String>>();
String selectQuery = "SELECT * FROM photo";
SQLiteDatabase database = this.getWritableDatabase();
Cursor cursor = database.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
HashMap<String, String> map = new HashMap<String, String>();
map.put("photoId", cursor.getString(0));
map.put("photoName", cursor.getString(1));
wordList.add(map);
} while (cursor.moveToNext());
}
// return contact list
return wordList;
}
public HashMap<String, String> getPhotoInfo(String id) {
HashMap<String, String> wordList = new HashMap<String, String>();
SQLiteDatabase database = this.getReadableDatabase();
String selectQuery = "SELECT * FROM photo where photoId='"+id+"'";
Cursor cursor = database.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
//HashMap<String, String> map = new HashMap<String, String>();
wordList.put("photoName", cursor.getString(1));
//wordList.add(map);
} while (cursor.moveToNext());
}
return wordList;
}
}
你得到「照片創建」在logcat中調用'getAllPhoto'過嗎? – TWiStErRob 2014-12-06 11:28:05
沒有答案。只是爲了通知**另一個問題**:'String deleteQuery =「DELETE FROM photo where photoId ='」+ id +「'」;'是錯誤的:id是一個整數,它不想**'**圍繞其價值。 – 2014-12-06 11:35:54
只需從設備或模擬器卸載您的應用程序,然後再次嘗試安裝應用程序,這可能會工作 – 2014-12-06 11:41:55