JObject Webapi中的模型驗證

Question

使用JObject將數據傳遞給webapi，您如何執行JObject返回的對象的模型驗證？我正在使用angurlarjs進行綁定，併爲我的模型使用DTO。

[System.Web.Http.HttpPost] 
     public HttpResponseMessage InsertSchoolBranch(JObject jsonData) 
     { 

      try 
      { 
       dynamic json = jsonData;  
       JObject jbranchInfo = json.branchInfo; 
       JObject jbranchPolicy = json.branchPolicy; 


       var branchInfo = jbranchInfo.ToObject<SchoolBranch>(); 
       var branchPolicy = jbranchPolicy.ToObject<SchoolPolicy>(); 

       int schoolId = Convert.ToInt32(UserDataPieces(2)); 
       int userId = Convert.ToInt32(UserDataPieces(0)); 

       unitOfWork.SchoolManagerRepository.InsertSchoolBranch(branchInfo, branchPolicy, userId, schoolId, ref message); 

       return new HttpResponseMessage(HttpStatusCode.OK); 
      } 
      catch (UnauthorizedAccessException) 
      { 
       return Request.CreateResponse(HttpStatusCode.Unauthorized); 
      } 
      catch (Exception) 
      { 
       return Request.CreateResponse(HttpStatusCode.InternalServerError); 


      } 


     } 

Answer 1

如果要驗證輸入數據，請考慮使用自定義ActionFilterAttributes對其進行裝飾。

[RequiresJsonBody("SchoolBranch","SchoolPolicy")] 
public HttpResponseMessage InsertSchoolBranch(JObject jsonData) 
{ 
    // Stuff... 
} 

或可能使用一些元組爲模型

public class RequiresJsonBody : ActionFilterAttribute 
{ 
    private string paramName; 

    public RequiresJsonBody (string paramName) 
    { 
     this.paramName = paramName; 
    } 

    public override void OnActionExecuting(HttpActionContext actionContext) 
    { 
     IDictionary<string, string> errors = new Dictionary<string, string>(); 

     // Validate incoming. Add key/error messages to dictionary... 

     foreach (var err in errors) 
     { 
      actionContext.ModelState.AddModelError(err.Key, err.Value); 
     } 

     if (!actionContext.ModelState.IsValid 
      && errors.Keys.Count > 0) 
     { 
      actionContext.Response 
       = actionContext.Request.CreateErrorResponse(
        HttpStatusCode.BadRequest, 
        String.Join(" ", errors.Values.ToArray())); 
     } 
    } 
}