的Makefile：運行二進制文件不同，這取決於他們的名字

Question

我在Makefile中有這樣的：

BINS = $(shell echo *.bin) 

.PHONY: $(BINS) 
run: $(BINS) 

*.bin: 
    ./$@ 

我運行它make -j 8

這樣它看起來與.bin文件結尾的所有文件，並運行它們在使用make的-j選項（Makefile run processes in background）

平行我需要修改Makefile，使其運行類型MPI * .bin文件作爲mpirun -np 2 ./mpi*.bin的所有文件，剩下的可執行文件爲./<filename>.bin

感謝您的幫助。

Answer 1

舉個簡單的例子，我用來測試我的回答：根據你的

touch {a,b,c,d}.bin mpi{a,b,c,d}.bin 

創建一些空的測試文件，和我的Makefile：

BINS = $(shell echo *.bin) 

.PHONY: $(BINS) 
run: $(BINS) 

*.bin: 
    echo "bin file: " ./$@ 

mpi*.bin: 
    echo "mpi file: " ./$@ 

正是在這裏，關鍵前綴文件規則遵循未加前綴的規則。如果不是，則前綴規則將被覆蓋。

這似乎爲前綴和不帶前綴的文件之間進行區分的工作，但給出了以下的輸出：

~/tmp$ make 
Makefile:10: warning: overriding commands for target `mpia.bin' 
Makefile:7: warning: ignoring old commands for target `mpia.bin' 
Makefile:10: warning: overriding commands for target `mpib.bin' 
Makefile:7: warning: ignoring old commands for target `mpib.bin' 
Makefile:10: warning: overriding commands for target `mpic.bin' 
Makefile:7: warning: ignoring old commands for target `mpic.bin' 
Makefile:10: warning: overriding commands for target `mpid.bin' 
Makefile:7: warning: ignoring old commands for target `mpid.bin' 
echo "bin file: " ./a.bin 
bin file: ./a.bin 
echo "bin file: " ./b.bin 
bin file: ./b.bin 
echo "bin file: " ./c.bin 
bin file: ./c.bin 
echo "bin file: " ./d.bin 
bin file: ./d.bin 
echo "mpi file: " ./mpia.bin 
mpi file: ./mpia.bin 
echo "mpi file: " ./mpib.bin 
mpi file: ./mpib.bin 
echo "mpi file: " ./mpic.bin 
mpi file: ./mpic.bin 
echo "mpi file: " ./mpid.bin 
mpi file: ./mpid.bin 

我敢肯定，有抑制這些警告的方式或做的更好，但這種方法似乎有效。