2010-11-26 82 views
0

我做這個請求: $uid = db_query("SELECT uid FROM tablename WHERE mail = '[email protected]' LIMIT 1")SQL請求返回源ID

並獲得儘可能結果:

資源ID#310

但我想要得到的UID。錯誤在哪裏?

回答

0
db_query("SELECT uid FROM tablename WHERE mail = '[email protected]' LIMIT 1"); 

只是給你一個「答案」,但你想要它的價值。試試這個:

$result = db_query("SELECT uid FROM tablename WHERE mail = '[email protected]' LIMIT 1"); 
$row = db_fetch_array($result); 
$uid = $row[0]; 
+0

很酷。非常感謝您的回答。我剛剛開了一個新帖子,也許你也可以在這裏看到它? – Chris 2010-11-26 23:47:11