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我有這樣的JSON對象:如何使用jQuery通過鍵搜索和獲取json行數據?
{
"1234A":{
"apcdiv_staffname":"MOHD NASA",
"apcdiv_staffimage":"http://localhost/jknsapc/wp-content/uploads/2014/06/product-landing-layout-thumb.png",
"apcdiv_workplace":"HOSPITAL",
"apcdiv_grade":"U44",
"apcdiv_position":"PEGAWAI FARMASI",
"apcdiv_ic":"1234567"
},
"1234B":{
"apcdiv_staffname":"MOHTAR",
"apcdiv_staffimage":"http://localhost/jknsapc/wp-content/uploads/2014/06/product-landing-layout-thumb.png",
"apcdiv_workplace":"HOSPITAL",
"apcdiv_grade":"U44",
"apcdiv_position":"PERGIGIAN",
"apcdiv_ic":"7654321"
},
我要搜索,並通過使用密鑰讀取JSON行數據。例如,如果我使用密鑰1234B進行搜索,它將返回屬於1234B密鑰的數據。從那裏我可以繼續抓住數據裏面,如apcdiv_staffname
"1234B":{
"apcdiv_staffname":"MOHTAR",
"apcdiv_staffimage":"http://localhost/jknsapc/wp-content/uploads/2014/06/product-landing-layout-thumb.png",
"apcdiv_workplace":"HOSPITAL",
"apcdiv_grade":"U44",
"apcdiv_position":"PERGIGIAN",
"apcdiv_ic":"7654321"
}
如何使用jQuery實現它?我試圖谷歌,但無法找到相關的答案,也許是因爲我選擇的關鍵字。如果使用PHP陣列,我可以簡單地使用此代碼:
$object_row = $object['1234B'];
$apcdiv_staffname = $object_row['apcdiv_staffname'];
謝謝你們!
'VAR object_row = object.1234B' – 2015-04-06 02:21:28