「從哪裏是空刪除」我有一個關係使用HQL移除項條款
tag <-m:n-> software
內的兩個實體,我想刪除這不是鏈接標記刪除特定的標籤後,再全部軟件。我寫的HQL查詢的..
我使用playframework
我重寫Tag.delete()
@Override
public Tag delete() {
Tag t = null;
// t = super.delete(); // commented for now
// it should delete ONLY that softwares which are not linked with tags (tags is empty)
Query q = Tag.em().createQuery("delete from Software s where s.tags is empty ");
q.executeUpdate();
return t;
}
我的測試:
@Test
public void testDelete() throws InterruptedException {
Tag tag1 = new Tag("tag1").save();
Tag tag2 = new Tag("tag2").save();
Author author1 = new Author("name", "email").save();
Software s1 = new Software("soft1", "description1", author1, tag1).save(); // this should be deleted when tag1 is deleting
Software s2 = new Software("soft2", "description2", author1, tag1, tag2).save(); // this should be deleted, because it links to tag2
// checks, just in case:
Software ss = Software.findById(s1.id);
assertTrue(ss.isPersistent());
assertTrue(!ss.tags.isEmpty());
assertEquals(1, ss.tags.size());
tag1.delete();
// try to find the software
assertEquals(1, Software.findAll().size()); // here it faults, it deletes all!!!
}
現在我有問題它會刪除所有軟件,即使它們有鏈接到標籤。這是從HQL形成
,但我得到的SQL是這樣的:
delete from Software where not (exists (select tag.id from Tag_Software ts, Tag tag where Software.id=ts.softwares_id and ts.tags_id=tag.id))
,這是很好的SQL(我檢查),但爲什麼這一切不爲HQL工作我的背景......?
我的測試說:
故障,預計:< 1>卻被:< 0>
兩個類的代碼是:
public class Tag extends Model {
@Column(nullable = false, unique = true)
public String title;
public Tag(String title) {
this.title = title;
}
@ManyToMany
public List<Software> softwares = new LinkedList<Software>();
....
@Entity
public class Software extends Model {
public String title;
public String description;
@ManyToOne(optional = false)
public Author author;
@ManyToMany(mappedBy = "softwares")
public List<Tag> tags = new LinkedList<Tag>();
...
見http://stackoverflow.com/questions/5368522/why-this-hibernate-template-bulkupdate-doesnt-work/5369277# 5369277 – axtavt 2011-03-21 16:22:31
從A a中刪除[a.bs爲空| a.bs.size = 0 |大小(a.bs)= 0]適用於我。你的映射的細節? – ssedano 2011-03-21 16:40:31