號碼模式截止

Question

public class numPattern { 
    public static void main(String[] args) { 
     int digit1 = 2; 
     int digit2 = 7; 
     int tal = 0; 

     System.out.print(digit1 + " "); 
     System.out.print(digit2 + " "); 

     while (tal < 550) { 
      tal = digit1 + digit2; 

      System.out.print(tal + " "); 

      digit1 = digit2; 
      digit2 = tal; 
     } 
    } 
} 

此輸出2, 7, 9, 16, 25, 41, 66......453 and 733

的問題應該在453停止，因爲733是大大超過550

什麼命令將確保該程序在453結束，以滿足更大的或等於550我試圖尋找？

Answer 1

簡單的變化：

while (tal < 550){ 
    tal = digit1 + digit2; 

    System.out.print(tal + " "); 
    digit1 = digit2; 
    digit2 = tal; 
} 

到：

while (tal < 550) { 
    System.out.print(tal + " "); 

    digit1 = digit2; 
    digit2 = tal; 
    tal = digit1 + digit2; 
} 

和tal的初始化：
從int tal = 0，到int tal = digit1 + digit2;

Answer 2

只是跳過的digit2打印輸出，初始化tal爲相同的值，並重新排列在你的循環中的語句：

int digit1 = 2; 
System.out.print(digit1 + " "); 

int digit2 = 7; 
int tal = digit2; 
while (tal < 550) { 
    System.out.print(tal + " "); 
    tal = digit1 + digit2; 
    digit1 = digit2; 
    digit2 = tal; 
} 

Answer 3

增加的tal值在while：

int digit1 = 2; 
    int digit2 = 7; 
    int tal = 0; 

    System.out.print(digit1 + " "); 
    System.out.print(digit2 + " "); 

    while((tal = digit1 + digit2)< 550) 
    { 

     System.out.print(tal + " "); 

     digit1 = digit2; 
     digit2 = tal; 
    } 

Answer 4

int digit1 = 2; 

System.out.print(digit1 + " "); //it will print digit1 
do not print digit2 

int digit2 = 7; 
int tal = digit2; 
while (tal < 550) { 
    System.out.print(tal + " "); 
    tal = digit1 + digit2; 
    digit1 = digit2; 
    digit2 = tal; 
} 

因爲在循環首先增加值，然後打印因此前的狀態說假它已經在tal = 443時打印該值，然後它進入while循環執行總和並打印它，然後去檢查值

之後首先打印該值，然後執行總和並檢查其是否小於443