2
下面是代碼片段:如何使用安全瀏覽應用程序對象來確定是否將網址報告爲釣魚網站或惡意軟件網站?
Components.classes['@mozilla.org/safebrowsing/application;1']
.getService().wrappedJSObject.malwareWarden.listManager_
.safeLookup(test_url, function(tableName){
if (tableName == 'goog-phish-shavar' || tableNmae == 'goog-malware-shavar') {
alert('This is reported by Google! ');
};
});
它工作正常,但我不認爲這是「正確」的方法...
如果用戶有什麼改變的DataProvider?
代碼參考:http://mxr.mozilla.org/mozilla-central/source/browser/components/safebrowsing/content/ – 2010-09-17 04:39:51