0
這裏是我的輸入XML:如何通過使用XML的XSLT過濾器的XML PARAMS
<Books>
<Book>
<BookId>1</BookId>
<Des>Dumm1</Des>
<Comments/>
<OrderDateTime>04/06/2009 12:37</OrderDateTime>
</Book>
<Book>
<BookId>2</BookId>
<Des>Dummy2</Des>
<Comments/>
<OrderDateTime>04/07/2009 12:37</OrderDateTime>
</Book>
<Book>
<BookId>3</BookId>
<Des>Dumm12</Des>
<Comments/>
<OrderDateTime>05/06/2009 12:37</OrderDateTime>
</Book>
<Book>
<BookId>4</BookId>
<Des>Dummy2</Des>
<Comments/>
<OrderDateTime>06/07/2009 12:37</OrderDateTime>
</Book>
</Books>
我傳遞一個XML PARAM和我的輸入XML是
<BookIDs>
<BookID>2</BookID>
<BookID>3</BookID>
</BookIDs>
我的輸出應該是這樣的
<Books>
<Book>
<BookId>2</BookId>
<Des>Dummy2</Des>
<Comments/>
<OrderDateTime>04/07/2009 12:37</OrderDateTime>
</Book>
<Book>
<BookId>3</BookId>
<Des>Dumm12</Des>
<Comments/>
<OrderDateTime>05/06/2009 12:37</OrderDateTime>
</Book>
</Books>
如何使用XSLT完成此操作?
您能先發布您的嘗試嗎? – 2009-07-08 18:17:24