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我試過this answer的解決方案,但它沒有奏效。它導致以下SQL:如何在Propel中多次加入表格本身?
SELECT user.id AS `Id`, user.name AS `Name`,
AS `ReferralUser.Id`, AS `ReferralUser.Name`
FROM `ReferralUser` INNER JOIN `account` ON (ReferralUser.id=account.id)
請注意,ReferralUser不是我的數據庫中的表,它的意思是別名。
我需要至少兩次加入一個表格,但可能會在將來更多。我當前的代碼:
$q = \UserQuery::create();
$q->select(array('Id', 'Name',
'ReferralUserRelation.Id', 'ReferralUserRelation.Name',
'CreatorUserRelation.Id', 'CreatorUserRelation.Name'));
$q->join('ReferralUserRelation');
$q->join('CreatorUserRelation');
$q->find();
導致下面的SQL:
SELECT user.id AS `Id`, user.name AS `Name`, user.id AS `ReferralUserRelation.Id`,
user.name AS `ReferralUserRelation.Name`, `user.id` AS `CreatorUserRelation.Id`,
`user.name` AS `CreatorUserRelation.Name` FROM `user`
INNER JOIN `user` ON (user.id=user.referral_user_id)
INNER JOIN `user` ON (user.id=user.creator_user_id)
在行走這甚至可能嗎?