我正在嘗試做我的功課,而且我似乎遇到了錯誤。我必須建立一個矩形並返回周長和麪積,矩形的默認高度和寬度都是1.一切看起來都不錯,直到我編譯它,然後我被告知主要方法必須是靜態的。當我使主要方法爲靜態時,然後我得到「無法從靜態上下文中引用的非靜態變量」錯誤。我需要做什麼來解決它的任何想法?創建兩個Rectangle對象的問題
package rectangle;
/**
*
* @author james
*/
public class Rectangle {
/** Main Method */
public static void main(String[] args) {
//Create a rectangle with width and height
SimpleRectangle rectangle1 = new SimpleRectangle();
System.out.println("The width of rectangle 1 is " +
rectangle1.width + " and the height is " +
rectangle1.height);
System.out.println("The area of rectangle 1 is " +
rectangle1.getArea() + " and the perimeter is " +
rectangle1.getPerimeter());
//Create a rectangle with width of 4 and height of 40
SimpleRectangle rectangle2 = new SimpleRectangle(4, 40);
System.out.println("The width of rectangle 2 is " +
rectangle2.width + " and the height is " +
rectangle2.height);
System.out.println("The area of rectangle 2 is " +
rectangle2.getArea() + " and the perimeter is "
+ rectangle2.getPerimeter());
}
public class SimpleRectangle {
double width;
double height;
SimpleRectangle() {
width = 1;
height = 1;
}
//Construct a rectangle with a specified width and height
SimpleRectangle(double newWidth, double newHeight) {
width = newWidth;
height = newHeight;
}
//Return the area of the rectangle
double getArea() {
return width * height;
}
//Return the perimeter of a rectangle
double getPerimeter() {
return (2 * width) * (2 * height);
}
}
}
請確保您將包含* exact *錯誤消息,即將其剪切並粘貼到問題中。 – Dancrumb 2013-03-18 01:29:06
並且請在這裏顯示一個明顯的註釋,例如發生編譯器錯誤的'****** error here ****'。 – 2013-03-18 01:30:11
嗯.. ahhhh .. ummmm ...沒關係...愚蠢的支架.... – user2154095 2013-03-18 01:30:33