如何使用php，msqli提交從一個表到另一個表

Question

我有以下php搜索腳本。

<?php 
    $query = $_GET['query']; 
    // gets value sent over search form 

    $min_length = 3; 
    // you can set minimum length of the query if you want 

    if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then 

     $query = htmlspecialchars($query); 
     // changes characters used in html to their equivalents, for example: < to &gt; 

     $query = mysql_real_escape_string($query); 
     // makes sure nobody uses SQL injection 

     $raw_results = mysql_query("SELECT * FROM florinvtable 
      WHERE (`Brand` LIKE '%".$query."%') OR (`Description` LIKE '%".$query."%') OR (`Category` LIKE '%".$query."%') 
      ORDER BY Category, Brand, Price") or die(mysql_error()); 


     if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following 

      while($results = mysql_fetch_array($raw_results)){ 
      // $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop 

       echo "<div style='position:relative; font-size:18px; width:500px;'><span style='font-size:14px'>".$results['Category']."</span> - <strong>".$results['Brand']."</strong> - ".$results['Description']." - <span style='color:red;'>$".$results['Price']."</span> ".$results['Size']."</div>"; 
       // posts results gotten from database(title and text) you can also show id ($results['id']) 
      } 

     } 
     else{ // if there is no matching rows do following 
      echo "No results"; 
     } 

    } 
    else{ // if query length is less than minimum 
     echo "Minimum length is ".$min_length; 
    } 
?> 

我想爲每行顯示的提交按鈕顯示，我可以點擊複製一行到同一個單獨的表。你可能會問，爲什麼要保存兩張相同的表格？答案是原始表經常被截斷。也就是說，如何使用下面的腳本將提交按鈕合併到上面的腳本中。

<?php  

$query = "INSERT INTO floradtable (Category, Brand, Price) 
      SELECT Category, Brand, Price FROM florinvtable 
      WHERE id='".$mysqli->real_escape_string($_REQUEST['id'])."' 
      LIMIT 0,1"; 

$mysqli->query($query); 
?> 

作爲一個方面說明，我知道我正在將mysqli與mysqli混合使用，在解決當前問題後我將解決這個問題。任何幫助表示讚賞。

Answer 1

加入此項。

if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following 
     $query = "INSERT INTO floradtable (Category, Brand, Price) VALUES"; 
     while($results = mysql_fetch_array($raw_results)){ 
     // $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop 
      $query .= "('".$results['Category']."','".$results['Brand']."','".$results['Price']."'),"; 
      echo "<div style='position:relative; font-size:18px; width:500px;'><span style='font-size:14px'>".$results['Category']."</span> - <strong>".$results['Brand']."</strong> - ".$results['Description']." - <span style='color:red;'>$".$results['Price']."</span> ".$results['Size']."</div>"; 
      // posts results gotten from database(title and text) you can also show id ($results['id']) 
     } 
     $query = substr($query, 0, -1);//to remove the trailing comma 
     $mysqli->query($query); 
    }