合併neo4j中的現有記錄，刪除重複項，保留可選關係

Question

這與Merge existing records in neo4j, remove duplicates, keep relationships類似，只是我想要合併的節點具有0-2的關係。

取所產生的圖形：

create (:Person {name:"Bob"})-[:RELATED_TO]->(:Person {name:"Jane"})-[:FRIENDS_WITH]->(:Person {name:"Tim"})<-[:FRIENDS_WITH]-(:Person {name:"Jane"}), 
(:Person {name:"Sally"})-[:RELATED_TO]->(:Person {name:"Jane"}) 

我想合併重複簡節點，保留RELATED_TO和FRIENDS_WITH關係，刪除重複項。

從另一個問題，我可以得到儘可能：

match (p:Person {name:"Jane"}) 
with p.name as name, collect(p) as ps, count(*) as pcount 
where pcount > 1 
with head(ps) as first, tail(ps) as rest 
unwind rest as to_delete 
return to_delete 

但我似乎無法得到正確的合併匹配和/或可選的比賽。我嘗試鏈接可選匹配，並在一個語句中進行合併，neo4j給我一個Statement.ExecutionFailure，沒有額外的消息。我試圖打破每場比賽的合併，並以「其他節點爲空」結束。思考？

Answer 1

以下查詢正在工作。在一個側面說明，對於這種重構的我很想有一天，將有可能設置一個動態變量的關係式：

MATCH (n:Person { name:"Jane" }) 
WITH collect(n) AS janes 
WITH head(janes) AS superJane, tail(janes) AS badJanes 
UNWIND badJanes AS badGirl 
OPTIONAL MATCH (badGirl)-[r:FRIENDS_WITH]->(other) 
OPTIONAL MATCH (badGirl)<-[r2:RELATED_TO]-(other2) 
DELETE r, r2, badGirl 
WITH superJane, collect(other) AS friends, collect(other2) AS related 
FOREACH (x IN friends | MERGE (superJane)-[:FRIENDS_WITH]->(x)) 
FOREACH (x IN related | MERGE (x)-[:RELATED_TO]->(superJane)) 

結果：