JSON返回格式

Question

阿比地址： http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone

回報：

KISSY.Suggest.callback({"result": [["iphone4s", "9809"], ["iphone5", "13312"], ["iphone4 手機", "69494400"], ["iphone5 港行", "14267"], ["iphone5三網", "2271160"], ["iphone4手機殼", "6199679"], ["iphone 5手機殼", "2527284"], ["iphone 5 保護殼", "5727586"], ["iphone 4貼膜", "147271"], ["iphone5殼", "2628540"]]}) 


NSURL * url = [NSURL URLWithString:@"http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone"]; 
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; 

NSHTTPURLResponse* urlResponse = nil; 

NSError * error = nil; 

NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error]; 

NSData *date = [NSData alloc]init 

SBJsonParser *jsonParser = [[SBJsonParser alloc] init]; 


// NSMutableArray *array=[NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableLeaves error:&error]; 
    NSMutableArray *array = [jsonParser objectWithData:responseData]; 

    NSLog(@"%@",array); 

這個數組爲空。我不知道原因。

Answer 1

因爲我指你請求的URL，它有回調，如果你保留它，它不會返回你json a的反應，所以從您的網址

// Make sure you have include SBJSON files in your Project, as well you have imported header in your View Controller 
#import "JSON.h" 

// your request URL 
NSURL * url = [NSURL URLWithString:@"http://suggest.taobao.com/sug?area=etao&code=utf-8&q=iphone"]; 

// URL Request 
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; 

NSHTTPURLResponse* urlResponse = nil; 

NSError * error = nil; 

// initiate Request to get Data 
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error]; 

// Encode your Response 
NSString *content = [[NSString alloc] initWithBytes:[responseData bytes] length:[responseData length] encoding:NSUTF8StringEncoding]; 

// Now read a Dictionary from it using SBJSON Parser 
NSDictionary *responseDict = [content JSONValue]; 

NSLog(@"Response [%@]",responseDict); 

Answer 2

我不熟悉的SBJsonParser，但返回的字符串的格式看起來像JSONP，JSON不是。我想可能只是簡單地清理一下包裝器的調用會讓你知道你在做什麼。

此外，請注意，你的響應的「根」是一個字典，而不是陣列。

{"result": [[... 

意味着代碼可能應該是這樣的：

NSDictionary *response = //... decode 
NSArray *results = [response objectForKey:@"result"]; 

Answer 3

編輯

你只需要使用http://suggest.taobao.com/sug?area=etao&code=utf-8&q=iphone而不是http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone你自己的代碼會運行