Android Studio - 如何導出其中有其他罐子的罐子？

Question

我使用下面的gradle生成.jar文件

當我使用下面的gradle導出時，我能夠生成.jar文件，但它沒有附加依賴MyJar文件。

apply plugin: 'com.android.library'//To generate Jar 

android { 
    compileSdkVersion 24 
    buildToolsVersion "25.0.0" 
    sourceSets { 
     main { 
      //Path to My source code 
      java { 
       srcDir 'src/main/java' 
      } 
     } 
    } 
    defaultConfig { 

     minSdkVersion 15 
     targetSdkVersion 24 

    } 
    buildTypes { 
     release { 
      minifyEnabled false 
      proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro' 
     } 
    } 

} 

dependencies { 
    compile fileTree(include: ['*.jar'], dir: 'libs') 
    androidTestCompile('com.android.support.test.espresso:espresso-core:2.2.2', { 
     exclude group: 'com.android.support', module: 'support-annotations' 
    }) 
    compile 'com.android.support:appcompat-v7:24.2.1' 
    testCompile 'junit:junit:4.12' 
    compile files('libs/MyJar.jar')//MyJar When generating the Jar this is not include by gradle? 
} 

//task to delete the old jar 
task deleteOldJar(type: Delete) { 
    delete 'release/ExportedJar.jar' 
} 

//task to export contents as jar 
task exportJar(type: Copy) { 
    from('build/intermediates/bundles/release/') 
    into('release/')  
    include('classes.jar') 
    //include('MyJar.jar')//Tried this but No luck  
    rename('classes.jar', 'ExportedJar.jar') 
} 

exportJar.dependsOn(deleteOldJar, build) 

如何實現這一目標？有沒有turnaround.Thanks提前

Answer 1

什麼，你想實現的是建立一個所謂的「胖罐」。

添加另一個任務可以在圖書館的build.gradle：

task fatJar(type: Jar) { 
    baseName = project.name + '-all' 
    from { configurations.compile.collect { it.isDirectory() ? it : zipTree(it) } } 
    with jar 
} 

，並通過命令行調用：

gradlew fatJar 

---

如果你想從lib文件夾添加僅.jar的，然後加入到build.gradle：

jar { 
    into('lib') { 
     from 'libs' 
    } 
} 

而且從從命令行調用：

gradlew :{library_module_name}:jar