爲什麼我不能用yii項目中的關係做這個查詢？

Question

我想用Yii關係創建一個查詢。這是我的關係：

//Articles model 
return array(
      'articlesHasTags' => array(self::HAS_MANY, 'ArticlesHasTag', 'articles_id', 
          "with"=>"tag", 
          ), 
          ), 
//ArticlesHasTag model 
     return array(
      'articles' => array(self::BELONGS_TO, 'Articles', 'articles_id'), 
      'tag' => array(self::BELONGS_TO, 'Tag', 'tag_id'), 
     ); 

這是查詢：

$blog = Articles::model()->with(array("articlesHasTags"))->findAllByAttributes(array(),array(
     "condition"=>"t.del = 0 AND t.active = 1 AND articlesHasTags.tag_id = {$tag->id}", 
     'order'=>"t.publish_start DESC", 
     "limit"=>10, 
    )); 

之前，我的$tag->id。

的錯誤信息是：

未知列 'articlesHasTags.tag_id'

我覺得關係很好，因爲我可以使用它，而這個 「articlesHasTags.tag_id = {$tag->id}」

我改變與表名稱的關係名稱。然後完整的錯誤信息是：

CDbCommand未能執行SQL語句：SQLSTATE [42S22]： 柱未發現：在 1054未知列'articles_has_tag.tag_id 'where子句'。執行的SQL語句是：SELECT t。 id AS t0_c0，t。 active AS t0_c1，t。 publish_start AS t0_c2， t。 publish_start_local AS t0_c3，t。 create_time AS t0_c4， t。 last_modify AS t0_c5，t。 title AS t0_c6，t。 url AS t0_c7，t。 short_desc AS t0_c8，t。 content AS t0_c9， t。 image AS t0_c10，t。 comment AS t0_c11，t。 hightlight AS t0_c12，t。 vote AS t0_c13，t。 type AS t0_c14, t。 users_id AS t0_c15，t。 newspaper_id AS t0_c16，t。 del AS t0_c17，t。 region_id AS t0_c18，t。 language_id AS t0_c19，t。 adult AS t0_c20，users。 id AS t1_c0， users。 email AS t1_c1，users。 password AS t1_c2， users。 author_name AS t1_c3，users。 location AS t1_c4, users。 last_login AS t1_c5，users。active AS t1_c6, users。 remember_me AS t1_c7，users。 rank AS t1_c8, users。 paypal_acc AS t1_c9，users。 url AS t1_c10, users。 about_me AS t1_c11，users。 image AS t1_c12， users。 facebook AS t1_c13，users。 google AS t1_c14, users。 del AS t1_c15，users。 admin_active AS t1_c16, users。 create_time AS t1_c17，users。 first_name AS t1_c18, users。 last_name AS t1_c19，newspaper。 id AS t4_c0, newspaper。 name AS t4_c1，newspaper。 create_time AS t4_c2， newspaper。 type AS t4_c3，newspaper。 active AS t4_c4， newspaper。 url AS t4_c5，newspaper。 location AS t4_c6， newspaper。 newspaper_category_id AS t4_c7 FROM articlest LEFT OUTER JOIN usersusers ON（t。users_id = users。id）LEFT OUTER JOIN newspapernewspaper ON （t。newspaper_id = newspaper。id）WHERE（t.del = 0 AND t.active = 1 AND articles_has_tag.tag_id = 42）ORDER BY t.publish_start DESC LIMIT 10

這裏是articles_has_tag表

CREATE TABLE IF NOT EXISTS `articles_has_tag` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `articles_id` int(11) DEFAULT NULL, 
    `tag_id` int(11) DEFAULT NULL, 
    `date` datetime DEFAULT NULL, 
    PRIMARY KEY (`id`), 
    KEY `fk_articles_has_tag_tag1_idx` (`tag_id`), 
    KEY `fk_articles_has_tag_articles1_idx` (`articles_id`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=93 ; 

Answer 1

爲什麼你沒有使用findAll？你把所有東西都放在條件下 而在SQL中提到的第二件事是你沒有關係articlesHasTags。

你可以試試這個。

$blog = Articles::model() 
    ->with("articlesHasTags" => array(
     'alias' => 'articlesHasTags', 
     'together' => true, //join in single query 
     'condition' => "articlesHasTags.tag_id = {$tag->id}"//may be use param? 
    ))->findAll(array(
     "condition"=>"t.del = 0 AND t.active = 1", 
     'order'=>"t.publish_start DESC", 
     "limit"=>10, 
    )); 

Answer 2

更新時間： 試試這個。

$blog = Articles::model()->with(array('articlesHasTags' => array(
     'alias'=>'articleHTag', 'condition' => "articleHTag.tag_id = ".$tag->id)))->findAllByAttributes(array(),array(
     "condition"=>"t.del = 0 AND t.active = 1", 
     'order'=>"t.publish_start DESC", 
     "limit"=>10, 
    ));