1
在下面的剪輯中,我正在計算文件的位置以查找,以便寫入。tellp正在返回錯誤的值
然後我嘗試打印那個位置。它返回一個不正確的值;
printf("nXBlocks: %i nYBlocks: %i posX: %i, posY: %i, blockheight: %i, blockwidth: %i \n",
nXBlocks,nYBlocks, tilePosX, tilePosY , XBlockSize, YBlockSize);
binfile->seekp((tilePosX*poBand->GetYSize()*XBlockSize)*sizeof(uint16_t) + (tilePosY * XBlockSize*YBlockSize)*sizeof(uint16_t));
size_t pos = binfile->tellp();
cout<<"Multiplication output: "
<<(tilePosX*poBand->GetYSize()*XBlockSize)*sizeof(uint16_t) + (tilePosY * XBlockSize*YBlockSize)*sizeof(uint16_t)
<<endl;
cout << "Put pointer positions: " << pos << endl;
binfile->write((char *)&sixteenBitData, sizeof(uint16_t)*bufSizeX*bufSizeY);
我得到的
置入指針位置的輸出:基於我傳遞給seekp
值18446744073709551615對於每次調用tellp
相反值
編輯:一些輸出的前幾...
nXBlocks: 34 nYBlocks: 29 posX: 0, posY: 0, blockheight: 1024, blockwidth: 1024
Multiplication output: 0
Put pointer positions: 0
nXBlocks: 34 nYBlocks: 29 posX: 0, posY: 1, blockheight: 1024, blockwidth: 1024
Multiplication output: 2097152
Put pointer positions: 18446744073709551615
nXBlocks: 34 nYBlocks: 29 posX: 0, posY: 2, blockheight: 1024, blockwidth: 1024
Multiplication output: 4194304
Put pointer positions: 18446744073709551615
該文件是否以二進制打開? –
因爲這是C++問題,所以使用std :: cout來打印。然後你將保證在打印時獲得正確的類型。而不是使用「zu」,這似乎是格式化的C99擴展。 –
是的,它是二進制 – Derek