MySQL：如何返回每個唯一編號的最近一行

在下表中，我不確定如何執行此操作，但我該如何着手編寫查詢，該查詢返回每個唯一PhoneNumber的最新行？MySQL：如何返回每個唯一編號的最近一行

PhoneNumber MessageText    ReceiveTime   
------------- ------------------------ ------------------- 
+639148186649 Delivery please   2013-03-19 01:12:55 
+639148186649 I need this item   2013-03-22 02:15:01 
+639148186649 I need more of this item 2013-03-23 12:01:02 
+639194357455 How much for this...  2013-03-24 16:36:33 
+639194357455 What time do you open? 2013-03-24 17:55:07

來源

2013-03-29 enchance

您無法按一列分組並返回不依賴於該組的其他列。有關提示，請參閱this question的答案。

來源

2013-03-29 22:51:27 cdonner

我認爲這應該工作...

SELECT * 
FROM PhoneTable 
GROUP BY PhoneNumber 
HAVING ReceiveTime = MAX(ReceiveTime) 
ORDER BY ReceiveTime

..或者你可能不得不做這樣的事情......

SELECT PhoneNumber, MessageText, ReceiveTime 
FROM PhoneTable t 
WHERE ReceiveTime = (SELECT MAX(ReceiveTime) 
        FROM t 
        GROUP BY PhoneNumber 
        HAVING PhoneNumber = t.PhoneNumber)

來源

2013-03-29 23:03:54 Leng

不應該鼓勵使用'GROUP BY'。 – Kermit

這兩個錯誤。 '錯誤代碼：1242 子查詢返回多於一行' – enchance

我找到了答案！

SELECT s1.PhoneNumber, s1.MessageText, s1.ReceiveTime FROM mytable s1 LEFT JOIN mytable s2 
    ON (s1.PhoneNumber = s2.PhoneNumber AND s1.ReceiveTime < s2.ReceiveTime) 
    WHERE s2.ReceiveTime IS NULL ORDER BY ReceiveTime DESC

來源

2013-03-29 23:48:08 enchance

MySQL：如何返回每個唯一編號的最近一行

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