Swift 2.3到Swift 3.0獲取模糊引用錯誤給成員'joined'

Question

我正在將swift swift 2.3轉換爲swift 3.0;

雨燕2.3代碼：

extension ContextDidSaveNotification: CustomDebugStringConvertible { 
    public var debugDescription: String { 
     var components = [notification.name] 
     components.append(managedObjectContext.description) 
     for (name, set) in [("inserted", insertedObjects), ("updated", updatedObjects), ("deleted", deletedObjects)] { 
      let all = set.map { $0.objectID.description }.joinWithSeparator(", ") 
      components.append("\(name): {\(all)}") 
     } 
     return components.joinWithSeparator(" ") 
    } 
} 

雨燕3.0代碼：

extension ContextDidSaveNotification: CustomDebugStringConvertible { 
    public var debugDescription: String { 
     var components = [notification.name] 
     components.append(Notification.Name(rawValue: managedObjectContext.description)) 
     for (name, set) in [("inserted", insertedObjects), ("updated", updatedObjects), ("deleted", deletedObjects)] { 
      let all = set.map { $0.objectID.description }.joined(separator: ", ") 
      components.append(Notification.Name(rawValue: "\(name): {\(all)}")) 
     } 
     return components.joined(separator: " ") 
    } 
} 

但我得到的錯誤：不明確的參考memeber '加入（）'爲落色回報在Swift 3.0代碼中。

如何解決這個問題？我做了很多研究，但找不到工作解決方案。

感謝

Answer 1

joined(separator:)聲明爲Array<String>，不Array<Notification.Name>：

// somewhere in standard library 
extension Array where Element == String { 

    public func joined(separator: String = default) -> String 
} 

由於@vadian指出，Notification.Name不等同於String，所以你需要你的數組先轉換。這應該工作：

components 
    .map({ $0.rawValue }) 
    .joined(separator: " ")