如何通過mysql檢索所有患者的溫度信息？

Question

我在我的數據庫中有三張桌子，一張是病人，一張是他們的溫度，另一張桌上是病人的身份證和溫度的ID作爲主鍵。

病人表;

+----+------+--------+------------+ 
| id | name | gender | birth  | 
+----+------+--------+------------+ 
| 1 | Hind | F  | 2015-01-01 | 
| 2 | Saad | M  | 2016-01-01 | 
+----+------+--------+------------+ 

patient_info表：

+------+------+ 
| id_t | id_p | 
+------+------+ 
| 1 | 1 | 
| 1 | 2 | 
| 2 | 3 | 
| 2 | 4 | 
+------+------+ 

下表：

+----+-------------+ 
| id | temperature | 
+----+-------------+ 
| 1 |  37.9 | 
| 2 |   37 | 
| 3 |   38 | 
| 4 |  38.4 | 
+----+-------------+ 

所以，我想要的是檢索所有患者的溫度，這裏是我做了什麼：

mysql> SELECT p.*, t.* FROM patient p INNER JOIN patient_info pi ON pi.id_p = p.id INNER JOIN temperature t ON t.id = pi.id_t; 
+----+------+--------+------------+----+-------------+ 
| id | name | gender | birth  | id | temperature | 
+----+------+--------+------------+----+-------------+ 
| 1 | Hind | F  | 2015-01-01 | 1 |  37.9 | 
| 2 | Saad | M  | 2016-01-01 | 1 |  37.9 | 
+----+------+--------+------------+----+-------------+ 

但tha t不是我想要的，我需要知道所有Hind和Saad的溫度 謝謝全部

Answer 1

我希望你真的能夠像這樣 - 儘管將溫度存儲在單獨的表格中並沒有什麼意義。 ..

DROP TABLE IF EXISTS patient; 

CREATE TABLE patient 
(patient_id INT NOT NULL AUTO_INCREMENT PRIMARY KEY 
,name VARCHAR(12) NOT NULL 
,gender CHAR(1) NOT NULL 
,dob DATE NOT NULL 
); 

INSERT INTO patient VALUES 
(101 ,'Hind','F','2015-01-01'), 
(102 ,'Saad','M','2016-01-01'); 


DROP TABLE IF EXISTS patient_temperature; 

CREATE TABLE patient_temperature 
(patient_id INT NOT NULL 
,temperature_id INT NOT NULL 
,PRIMARY KEY(patient_id,temperature_id) 
); 

INSERT INTO patient_temperature VALUES 
(101,1), 
(101,2), 
(102,3), 
(102,4); 

DROP TABLE IF EXISTS temperature; 

CREATE TABLE temperature 
(temperature_id INT NOT NULL AUTO_INCREMENT PRIMARY KEY 
,temperature DECIMAL(5,2) NOT NULL 
); 

INSERT INTO temperature VALUES 
(1,37.9), 
(2,37), 
(3,38), 
(4,38.4); 

SELECT p.* 
    , t.* 
    FROM patient p 
    JOIN patient_temperature pt 
    ON pt.patient_id = p.patient_id 
    JOIN temperature t 
    ON t.temperature_id = pt.temperature_id; 
+------------+------+--------+------------+----------------+-------------+ 
| patient_id | name | gender | dob  | temperature_id | temperature | 
+------------+------+--------+------------+----------------+-------------+ 
|  101 | Hind | F  | 2015-01-01 |    1 |  37.90 | 
|  101 | Hind | F  | 2015-01-01 |    2 |  37.00 | 
|  102 | Saad | M  | 2016-01-01 |    3 |  38.00 | 
|  102 | Saad | M  | 2016-01-01 |    4 |  38.40 | 
+------------+------+--------+------------+----------------+-------------+