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當我嘗試在兩個序列化器之間創建嵌套關係時,出現AttributeError。奇怪的是我正在做與另一個API完全相同的事情,但這一次我沒有得到它的工作。下面是代碼:使用嵌套關係時的AttributeError
class UserSerializer(serializers.ModelSerializer):
class Meta:
model = get_user_model()
fields = ('id', 'last_login','username', 'created')
class NotificationSerializer(serializers.ModelSerializer):
user_id = UserSerializer()
class Meta:
model = Notification
fields = ('id', 'user_id', 'type', 'parent_id', 'created', 'modified', 'seen')
和相關機型:
class Notification(models.Model):
user = models.ForeignKey(User)
type = models.CharField(max_length=255)
parent_id = models.IntegerField()
created = models.DateTimeField(auto_now_add=True)
modified = models.DateTimeField(auto_now=True)
seen = models.SmallIntegerField(default=0)
def __unicode__(self):
return self.type
class Meta:
db_table = 'notification'
class User(AbstractBaseUser, PermissionsMixin):
username = models.CharField(max_length=255, unique=True)
id = models.IntegerField(primary_key=True)
created = models.DateTimeField(auto_now=True)
tag = models.ManyToManyField(Tag)
USERNAME_FIELD = 'username'
objects = MyUserManager()
class Meta:
db_table = 'user'
錯誤:
Exception Type: AttributeError
Exception Value:
'long' object has no attribute 'id'
Exception Location: /lib/python2.7/site-packages/rest_framework/fields.py in get_component, line 55
誰能幫我這個錯誤?正常的主鍵關係有效,但我肯定希望獲得嵌套關係。
謝謝!這是訣竅。 爲什麼使用自定義ID?因爲標準的生成一個自動增量字段,我不想要一個自動增量的id。我手動設置用戶標識(從另一個外部配置文件表)。這就是爲什麼 ;) – Leander