2012-03-22 99 views
-1

嗨,我嘗試以下選擇:當組屬性設置,用戶必須成爲會員:Hibernate的情況下,Where語句

FROM Appointment a WHERE (CASE WHEN a.group!=null THEN :user MEMBER OF a.group.groupMembers ELSE true END) 

,但我得到:

org.hibernate.hql.ast.QuerySyntaxException: unexpected token: MEMBER near line 1, column 88 [FROM de.lyth.appointment.model.Appointment a WHERE (CASE when a.group!=null THEN :user MEMBER OF a.group.groupMembers ELSE true END) ] 

怎麼能我這樣做?

感謝

編輯: 我解決它通過改變爲:

(a.group==null OR :user MEMBER OF a.group.groupMembers) 
+0

添加您的解決方案作爲答案並接受它。 – ManuPK 2012-03-22 13:48:51

+0

對不起,我沒有足夠的聲譽 – wutzebaer 2012-03-22 14:03:20

回答

-1

我解決它通過改變爲: (a.group == null或:a.group用戶成員。 groupMembers)

+1

那麼這是否意味着什麼時候不支持hql where子句? – 2016-02-17 20:17:14